Y = 5x + 2
3x = y + 10
3x = y + 10
3x = 5x + 2 + 10
3x = 5x + 12
3x - 5x = 12
-2x = 12
x = -6
substitute x = -6 into y = 5x + 2
y = 5(-6) + 2
y = -30 + 2
y = -28
x = -6, y = -28
hope this helped, God bless!
The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).


Therefore, 

t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :

= 0.020908803
The p value is 0.0209

So we reject the null hypothesis and conclude that 
Answer:
Approximately 22.97 years
Step-by-step explanation:
Use the equation for continuously compounded interest, which uses the exponential base "e":

Where P is the principal (initial amount of the deposit - unknown in our case)
A is the accrued value (value accumulated after interest is compounded), in our case it is not a given value but we know that it triples the original deposit (principal) so we write it as: 3 P (three times the principal)
k is the interest rate : 5% which translates into 0.05
and t is the time in the savings account to triple its value (what we need to find)
The formula becomes:

To solve for "t" we divide both sides of the equation by P (notice it cancels P everywhere), and then to solve for the exponent "t" we use the natural logarithm function:



Will there's
5.5 x 2 = 11
hope that helped
Answer:
$178.50
Step-by-step explanation:
Big brain go thinky-think.