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2 years ago

A small theater had 9 rows of 25 chairs each. Workers just removed 6 of these chairs. How many chairs are left?

Mathematics

2 answers:

marusya05 [52]2 years ago

8 0

Answer:

219 Chairs are left.

Step-by-step explanation:

$\rightarrow$ Each row has 25 chairs. And there are total 9 rows.

So, total number of chairs = 25×9

= 225

➾ Workers removed 6 chairs, so left number of chairs = 225-6

= 219 chairs.

____________________________________

Hope it helps you:)

Deffense [45]2 years ago

4 0

9 * 25 = 225

225 - 6 = 219

There are 219 chairs left.

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An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an

Alona [7]

Answer:

A. 0.5

B. 0.32

C. 0.75

Step-by-step explanation:

There are

28 students in the Spanish class,
26 in the French class,
16 in the German class,
12 students that are in both Spanish and French,
4 that are in both Spanish and German,
6 that are in both French and German,
2 students taking all 3 classes.

So,

2 students taking all 3 classes,
6 - 2 = 4 students are in French and German, bu are not in Spanish,
4 - 2 = 2 students are in Spanish and German, but are not in French,
12 - 2 = 10 students are in Spanish and French but are not in German,
16 - 2 - 4 - 2 = 8 students are only in German,
26 - 2 - 4 - 10 = 10 students are only in French,
28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

$\dfrac{50}{100} =0.5$

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

$\dfrac{8+10+14}{100}=0.32$

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

$0.5\cdot 0.5=0.25$

So, the probability that at least 1 is taking a language class is

$1-0.25=0.75$

3 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

Over the past week, 40% of the phone calls to Alicia's cell phone were from her son. Let's say you know that her son called her

ale4655 [162]

She received 12 calls from her son and 30 calls in total.

40% of 30 is 12.

5 0

2 years ago

In the general population, one woman in eight will develop breast

MArishka [77]

Answer:

a) 8/10

b) $0.001 \overline{33}$

c) Independent events

Step-by-step explanation:

The given information are;

The proportion of women than carries a mutation of the BRCA gene, P(A) = 1/600

The proportion of women in which the mutation develops breast cancer, P(B) = 8/10

a) The probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene is given as follows;

1 × P(B) = 1 × 8/10 = 8/10

b) The probability, P that a randomly selected woman woman will carry the mutation of the BRCA gene and will develop breast cancer is given as follows;

P(A) × P(B) = 1/600×8/10 = 1/750 = $0.001 \overline{33}$

c) The events are dependent

Given that P(A) × P(B) = P(A∩B), the events of carrying the mutation and developing Breast cancer are independent events.

4 0

3 years ago

Find g−1(x) when g(x)=3/5x−9.

weqwewe [10]

Answer:

−(2x)/(5)−9

Step-by-step explanation:

Replace the function designators in g−1x

with the actual functions.

(3/5x−9)−1x

Simplify (3/5x−9)−1x

−(2x)/(5)−9

5 0

3 years ago