Answer:
29.42 units
Step-by-step explanation:
<u>1) Find the perimeter around the semi-circle</u>
To do this, we find the circumference of the circle using the given diameter:
where d is the diameter
Plug in 6 as the diameter
Divide the circumference by 2
Therefore, the perimeter around the semi-circle is 3π units.
<u>2) Find the perimeter around the rest of the shape</u>
Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.
Therefore, we add the following:
7+6+7
= 20
Therefore, the perimeter around that area of the shape is 20 units.
<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>
Therefore, the perimeter of the shape is approximately 29.42 units.
I hope this helps!
<span>The term for the list of names randomly selected to form the jury pool is </span><span>venire.
Venire is </span>a<span> writ issued by a judge to a sheriff directing the summons of prospective jurors. Also called venire facias . The panel of prospective jurors from which a jury is selected.</span>
Answer:
y = x² - 2x - 8
Step-by-step explanation:
Given
y = (x - 4)(x + 2)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x + 2) - 4(x + 2) ← distribute parenthesis
= x² + 2x - 4x - 8 ← collect like terms
= x² - 2x - 8 ← in standard form
Answer:
y = 
x + 6.5
Step-by-step explanation:
We know that
A difference of two perfect squares (A² - B²) <span>can be factored into </span><span> (A+B) • (A-B)
</span> then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2
the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2
i <span> is called the </span><span>imaginary unit. </span><span>It satisfies </span><span> i</span>²<span> =-1
</span><span>Both </span><span> i </span><span> and </span><span> -i </span><span> are the square roots of </span><span> -1
</span><span>√<span> -2 </span></span> =√<span> -1• 2 </span><span> = </span>√ -1 •√<span> 2 </span> =i • <span> √<span> 2 </span></span>
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3= 0 + √2<span> <span>i
</span></span>x4= 0 - √2<span> i </span>
the answer is
the values of x are
x1=+√2
x2=-√2
x3= 0 + √2 i
x4= 0 - √2 i
