Answer:the number of cupcakes that Sue purchased is 12
Step-by-step explanation:
Let x represent the number of cupcakes that Sue purchased at the bakery.
Let y represent the number of cookies that Sue purchased at the bakery.
She needs to serve 36 people. This means she would purchase a total of 36 people. Therefore,
x + y = 36
Cupcakes cost $2.50 each, cookies cost $1.00 each. She spends $54.00. This means that
2.5x + y = 54 - - - - - - - - - 1
Substituting x = 36 - y into equation 1, it becomes
2.5(36 - y) + y = 54
90 - 2.5y + y = 54
- 2.5y + y = 54 - 90
- 1.5y = - 36
y = - 36/ - 1.5
y = =24
x = 36 - y = 36 - 24 = 12
Answer:
0.9608
Step-by-step explanation:
P = 56%
56% = 0.56
1-p
1-0.56
= 0.44
√p(1-p/n
= √0.56(1-0.56)/886
= √0.0002781
= 0.01667
= 0.017
0.59-0.56/0.017
= 1.76
P(z <1.76)
When we check the z table,
Probability is equal to 0.9608
Answer:
C. 120°
Step-by-step explanation:
There are two paralell lines, one is part of Angle B, and the other of Angle Q. Then there is a diagonal line, coming at the same angle from B all the way to Q, because the other two lines are paralell. It basically means if you were to slide the flat line which is connected to Q up the diagonal line, it would fit perfectly with it's parallel. So the two angles; Angle B and Angle Q; are the exact same.
Hope this helped! Good luck with future math problems :)
ANSWER
To graph the function

follow the steps below.
1. Find y- intercept by plugging in

.

is on the interval,

, so we substitute in to



Hence the y-intercept is

2. Find x-intercept by setting

This implies that

on

or

on

We now solve for

on each interval,

on

or

on

But observe that

does not belong to

This means it can never be an intercept for this piece-wise function.
Hence our x-intercept is

3. Plotting the boundaries of the interval.
For

on



.
This point

coincides with the x-intercept.


So we have the point

. But note that

does not belong to this interval so we plot this point as a hole.
For

on



So we plot



So we plot

also as a hole.
Plotting all these points we can now graph the function,

See attachment for graph.