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kifflom [539]
3 years ago
5

HELP PLEASE DUE NOW!! Does a line of best fit need to go through at least one point for there to be a correlation Also if a line

can go through the points on a scatter plot is there correlation???
Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

For a line of best fit, it doesn't nessesarily have to land on a point, it just has to be in between them or on them whichever way you choose to do it. And also your second question, yes it is correlation if it lines up with the line and not somewhere else or if there are so many dots that they don't really form a line then it isn't a correlation.

Hope this helps!

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Which function is shown in the graph below? PLEASE HELP ON A TIMER​
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y=log1/6x

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Write an equation of the line that passes (-3,3) and is perpendicular to the line 2y=8x-6
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2y=8x-30 or -4x+y=-15

Step-by-step explanation:

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Find the volume of a pyramid with a square base, where the perimeter of the base is 18.1 ft and the height of the pyramid is 28.
fomenos

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191.8

Step-by-step explanation:

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Let sin t = a​, cos t = b​, and tan t = c. Write the expression in terms of​ a, b, and c.
maks197457 [2]

Answer:

a+b-c

*Note c could be written as a/b

Step-by-step explanation:

-sin(-t - 8 π) + cos(-t - 2 π) + tan(-t - 5 π)

The identities I'm about to apply:

\sin(a-b)=\sin(a)\cos(b)-\sin(b)\cos(a)

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)

\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}

Let's apply the difference identities to all three terms:

-[\sin(-t)\cos(8\pi)+\cos(-t)\sin(8\pi)]+[\cos(-t)\cos(2\pi)+\sin(-t)\sin(2\pi)]+\frac{\tan(-t)-\tan(5\pi)}{1+\tan(-t)\tan(5\pi)}

We are about to use that cos(even*pi) is 1 and sin(even*pi) is 0 so tan(odd*pi)=0:

-[\sin(-t)(1)+\cos(-t)(0)]+[\cos(-t)(1)+\sin(-t)(0)]+\frac{\tan(-t)-0}{1+\tan(-t)(0)

Cleaning up the algebra:

-[\sin(-t)]+[\cos(-t)]+\frac{\tan(-t)}{1}

Cleaning up more algebra:

-\sin(-t)+\cos(-t)+\tan(-t)

Applying that sine and tangent is odd while cosine is even.  That is,

sin(-x)=-sin(x) and tan(-x)=-tan(x) while cos(-x)=cos(x):

\sin(t)+\cos(t)-\tan(t)

Making the substitution the problem wanted us to:

a+b-c

Just for fun you could have wrote c as a/b too since tangent=sine/cosine.

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