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exis [7]
2 years ago
8

terms in a geometric sequence are 16, 20, 25, 31.25, find the value of the 17th term, to the nearest WHOLE number.

Mathematics
1 answer:
Bond [772]2 years ago
8 0

Answer:

568

Explanation:

First you need to make an equation. You need to find the change, in this case it’s 1.25. After, you find that, you make your equation. A(n)=16(1.25)^n-1.

I hope this was helpful

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\large\boxed{f(4)=-1292}

Step-by-step explanation:

f(n)=-5f(n-1)-2\\\\f(1)=10\\\\f(2)=-5f(2-1)-2=-5f(1)-2\\\text{put}\ f(1)=10:\\f(2)=-5(10)-2=-50-2=-52\\\\f(3)=-5f(3-1)-2=-5f(2)-2\\\text{put}\ f(2)=-52\\f(3)=-5(-52)-2=260-2=258\\\\f(4)=-5f(4-1)-2=-5f(3)-2\\\text{put}\ f(3)=258\\f(4)=-5(258)-2=-1290-2=-1292

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