Rewrite <span>2cos x + 1 = 0 as:
2 cos x = -1, and then cos x = -1/2
x must be in Quadrant II or Quadrant III, since the adj. side is negative.
Note that the angle 120 has adj. side -1 and hyp 2. So 120 degrees is one solution.
Now what about a possible 2nd solution, to be found in Quadrant III? That would be -120 degrees, which has the same terminal line as does 240 degrees.
No soap.
So, the solution is 120 degrees.</span>
3 x^3 y^2
_______
8 ( y/x-3/2)
Answer:
1) 36
2) 190
3) 72 units
Step-by-step explanation:
1) 2x4 = 8 units area for rectangle
(4-2) x4 /2 = 4 units
6 x 4 = 24 units
8 + 4 + 24 = 36
2) 3 x 10 / 2 = 15 units
5 x 10 /2 = 25 units
15 x 10 = 150 units
150 + 25 + 15 = 190 units
3) 6 x 3 / 2 = 9 units
6 x 9 = 54 units
6 x 3 / 2 = 9 units
9 + 9 + 54 = 18 + 54 = 72 units
-3x+13=16
Move +13 to the other side. Sign changes from +13 to -13.
-3x+13-13=16-13
-3x=16-13
-3x=3
Divide by -3 for both sides.
-3/-3x=3/-3
Cross out -3 and -3, divide by -3, then becomes 1*1*x=x
x=-1
Answer: x=-1
A. Y= -7
X=2
4x+2y=-6
+(3x-2y=-8
