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alexira [117]
3 years ago
11

There are 5 types of candy sold in a store, at least 6 candies of each type. in how many ways can one buy n candies so that no t

ype of candy is selected more than 6 times?
Mathematics
1 answer:
Brrunno [24]3 years ago
6 0
 well you see i have no idea but i need to ask a question im sorry 
You might be interested in
Is a triangle with sides of length 6ft, 21 ft, 23 ft. A right triangle?
gayaneshka [121]

Answer:

No

Step-by-step explanation:

By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.

Thus, a^{2}+b^{2}=c^{2} where where a and b are the legs and c is the hypotenuse.

Let a=6ft, b=21ft and c=23ft, then

a^{2}+b^{2}=c^{2}

(6)^{2}+(21)^{2}=(23)^{2}

36+441=(23)^{2}

477=529

which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.


7 0
3 years ago
Ava is decorating cupcakes for a wedding.
PIT_PIT [208]

Answer:

21 are purple

63 are green

36 are yellow

Step-by-step explanation:

30% of 120 is 36

120 - 36 = 84

75% of 84 is  63

84 - 63 = 21

4 0
2 years ago
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
4x 10x h = 4x<br> h = 10x
s2008m [1.1K]

Step-by-step explanation:

the answer would be 40 4x 10x h = 4x

5 0
2 years ago
69. A 10-foot-tall basketball hoop is 4 feet shorter than twice the height of a flag pole.
bixtya [17]

Answer:

24 ft.

Step-by-step explanation:

10x2=20. 20+4=24

4 0
3 years ago
Read 2 more answers
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