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4 years ago

Δ+ + = 22 Δ+ 2 = 4 --Δ 2 + + =Δ

Mathematics

2 answers:

gizmo_the_mogwai [7]4 years ago

8 0

Answer:

Step-by-step explanation:

What do the trisynages mean

Serhud [2]4 years ago

4 0

you havent provided all the info needed to sove this problem

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I give brainliest

xxMikexx [17]

Functions are accurate through having one x intercepts which is how you can find which are functions or not.
Answer- B,D,E

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3 years ago

Of all the students in ms mack's class 44% are girls what ratio compares the number of girls in her class to the total number of

Mila [183]

44% = 44/100= 22/50= 11/25 so it would be 11 : 25

8 0

3 years ago

Identify the math property being applied 8 (y+9)

Volgvan

It's distribution

8(y+9)
8y + 72

3 0

3 years ago

What is the answer<br> 3 1/3 + 2 1/3

jek_recluse [69]

Answer:

5 2/3

Step-by-step explanation:

First add the whole numbers (3+2 = 5).

Then add the fractions. Since they already have common denominators, just add the numerators (1+1 = 2) and the denominator stays the same.

Since the numerator (top of the fraction) is smaller than the denominator (bottom of the fraction) and it can't be simplified, we are done. :-)

7 0

3 years ago

Read 2 more answers

For the function, find all critical numbers and then use the second-derivative test to determine whether the function has a rela

Serhud [2]

Answer:

relative maximum: x = 1

relative minimum: x = 7

Step-by-step explanation:

Critical points:

Values of x for which f'(x) = 0.

Second derivative test:

For a critical point, if f''(x) > 0, the critical point is a relative minimum.

Otherwise, if f''(x) < 0, the critical point is a relative maximum.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$f(x) = x^{3} - 12x^{2} + 21x - 8$

Finding the critical points:

$f'(x) = 3x^{2} - 24x + 21$

$3x^{2} - 24x + 21 = 0$

Simplifying by 3

$x^{2} - 8x + 7 = 0$

So $a = 1, b = -8, c = 7$

$\bigtriangleup = (-8)^{2} - 4*1*7 = 36$

$x_{1} = \frac{-(-8) + \sqrt{36}}{2} = 7$

$x_{2} = \frac{-(-8) - \sqrt{36}}{2} = 1$

Second derivative test:

The critical points are x = 1 and x = 7.

The second derivative is:

$f''(x) = 6x - 24$

$f''(1) = 6*1 - 24 = -18$

Since f''(1) < 0, at x = 1 there is a relative maximum.

$f''(7) = 6*7 - 24 = 18$

Since f''(x) > 0, at x = 7 there is a relative minumum.

8 0

3 years ago