Answer:
Step-by-step explanation:
Use appropriate formulas from geometry to evaluate the integral. Write the exact answer. Do not round.
1 answer:
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Answer:
m∠ MNL = 78º
Step-by-step explanation:
<u>Arcs meassures </u>
mML = (11x - 5)º
mJK = (4x + 26)°
<u>Angle meassure</u>
m∠MNL = (10 x – 12)º
______________________
angle measure = average of arcs
m∠MNL = (mML+ mJK)/2
Replacing
(10x – 12)º = ((11x - 5)º + (4x + 26)° )/ 2
10x -12 = (15x + 21 )/2
10x - 7.5x = 10.5 + 12
2.5x = 22.5
x= 9
m∠MNL = (10 x – 12)º
= 90 - 12
= 78º
The table when completed looks like this:
x -2 -1 0 1 2
f(x) 4 2 1 2 4.
We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).
<h3>What is a function?</h3>A function exists as a relation between a dependent variable (f(x)) and an expression of an independent variable (x), utilized to define the value of a dependent variable from a provided value of an independent variable.
We have been given a function,
We have to estimate the value of f(x) when x = {-2, -1, 0, 1, 2}
If the values of x ≤ 0, take f(x) = (1/2)ˣ then
f(-2) = (1/2)⁻² = 2² = 4
f(-1) = (1/2)⁻¹ = 2¹ = 2
f(0) = (1/2)⁰ = 1
If the values of x > 0, take f(x) = 2ˣ then
f(1) = 2¹ = 2
f(2) = 2² = 4
The table exists as follows
x -2 -1 0 1 2
f(x) 4 2 1 2 4.
We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).
To learn more about independent and dependent variable refer to:
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Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1