Which values of P and Qresult in an equation with no solutions? -60x+32=Qx+P
2 answers:
Answer:
Q is -60 and P is -32
Step-by-step explanation:
values of P and Q result in an equation with no solutions
When an equation have a no solution only when there is no x and both sides of equation are not same.
To eliminate x both sides of 'x' terms should be same
So Qx should be -60x
the value of Q= -60
To make both sides unequal , the value of p should be some other number
or opposite of 32
so p = -32
Add 60x on both sides
not same, its false
So , the equation has no solution
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Remember some simle log rules
loga+logb=log(ab)
xloga=loga^x
means 
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125
loga+logb=log(ab)
xloga=loga^x
also, if no base is stated, assume base 10
so
log(2x)=-1 is base 10 and translates to
10^-1=2x
1/10=2x
divide both sides by 2 aka times 1/2
1/20=x
3log(2)+log(x)=3
log(2^3)+log(x)=3
log(8)+log(x)=3
log(8x)=3
base 10
10^3=8x
1000=8x
divide both sides by 8
x=125