What is the number of grams in 1.25x10^25 molecules of aluminum oxide
1 answer:
Answer:
Mass = no. of molecules / 6.023 * 10^ 23 * Molar mass
Step-by-step explanation:
Molar mass of CO2 = 44g/mol
1.5
⋅
10
25
6.023
⋅
10
23
= 51.5 moles of CO2
51.5
⋅
44g/mol
=
2266 grams
Hope this helped
You might be interested in
Step 1: d = c-s/n
Step 2: dn = c-s
Solution is n = c-s/d :-)
Answer:
x=5 :)
Step-by-step explanation:
Answer:
JUST DOING THIS FOR POINTS
Step-by-step explanation:
LOL
how do i answer that I don't even know that sorry
1.001 is the smallest :)))
