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2 years ago

What is the number of grams in 1.25x10^25 molecules of aluminum oxide

Mathematics

1 answer:

aalyn [17]2 years ago

7 0

Answer:

Mass = no. of molecules / 6.023 * 10^ 23 * Molar mass

Step-by-step explanation:

Molar mass of CO2 = 44g/mol

1.5

⋅

6.023

⋅

= 51.5 moles of CO2

51.5

⋅

44g/mol

2266 grams

Hope this helped

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baherus [9]

Answer:

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Step-by-step explanation:

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2 years ago

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The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

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2 years ago

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yarga [219]

Answer:

C = 56.52 inches

Step-by-step explanation:

Given the following data;

Diameter, D = 18 inches

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To find the circumference of the circle;

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Circumference of circle, C = πD

Where, D is the diameter of a circle.

Substituting into the formula, we have;

C = 3.14 * 18

C = 56.52 inches

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2 years ago

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Answer:

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Step-by-step explanation:

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