Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
The loudness in decibels is
L = log₁₀(I/I₀)
where
I = sound intensity, W/m^2
I₀ = reference intensity, = 10^(-12) W/m^2
Raja's power level is 10^(-7) W, therefore the decibel value is
L = 10 log₁₀(10^(-7)/10^(-12))
= 10log₁₀10^5
= 10*5
= 50 dB
Answer: 50 dB
X² - 7x +12 = 0
(x-3)(x-4)=0
x= 3 or 4
since the leading coefficient is positive the parabola opens up and the vertex is a minimum
Answer:
Step-by-step explanation:
C = 16 * 3 = 48
