Answer: 108
Step-by-step explanation: 60% of 180 is 108
13m 16p
Add three to every number next as well as move up three letters.
For example:
1A is the starting point.
To get from 1A to 4D you add three.
1 + 3 = 4
A to get to D is three letters up.
A b c D
Same thing for 4D to get to 7G.
4 +3 = 7
D to get to G
D e f G
Your answer:
I'm not sure if you wanted me to find the letter of the equation or the actual next part. On your question you have just 13 up there, no letter so if youre trying to find the letter (13m) is your answer.
If you're trying to find the next equation to the puzzle (16p) is your answer.
Hope this helped!:)
Ok,
f(0.35)= 7f/20
f(-5.2)=-26f/5
f(10)= 10f
f(-0.5)= -f/2
as for the last question I am not quite sure, sorry....hope I helped a little :)
Answer:
Step-by-step explanation:
Considering the given triangle EDI, to determine ED, we would apply the sine rule. It is expressed as
a/SinA = b/SinB = c/SinC
Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes
ED/SinI = DI/SinE = EI/SinD
Therefore
Recall, the sum of the angles in a triangle is 180°. Therefore,
I° = 180 - (36 + 87) = 57°
Therefore,
ED/Sin 57 = 26/Sin 36
Cross multiplying, it becomes
EDSin36 = 26Sin57
0.588ED = 26 × 0.839
0.588ED = 21.814
ED = 21.814/0.588
ED = 37.1 m
Answer:
Step-by-step explanation:
There are 3 ways to find the other x intercept.
1) Polynomial Long Division.
Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.
2) Just solving for x when y = 0, by using the quadratic formula.
.
So the other x - intercept is at (1, 0)
3) Using Vietta's Theorem regarding the solutions of a quadratic
Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.
And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.
These relations between the solutions give us a brief idea of what the solutions should be like.
