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2 years ago

The diagram represents a 12cm by 4cm what is the area?

1 answer:

6 0

Well, to calculate the area, we would simply do length times width and we would get our area.
Area = Length * Width
Area = 12cm * 4cm
Area = 48cm squared.
So, in conclusion, the area is 48 cm squared.

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Marie is designing a bedspread for her grandsons new bedroom. 2/3 of the bedspread is covered in race cars, and the rest is stri

liraira [26]

Answer:

1/6

Step-by-step explanation:

2/3 of the bedspread is covered in race cars , therefore

1/3 of the bedspread is covered in stripes

2/4 of those 1/3 are red stripes

to find the fraction of the red stripes

2/4 x 1/3 = 2 / 12 = 1/6

4 0

1 year ago

The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?

Aliun [14]

$LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
LCM(x,y)=\dfrac{|x\cdot y|}{GCD(x,y)}\\
60=\dfrac{|x\cdot y|}{6}\\
|x\cdot y|=360\\\\\\
|x\cdot y|=360\\
x-y=18\\\\
|x\cdot y|=360\\
x=18+y\\\\
|(18+y)\cdot y|=360\\
|18y+y^2|=360\\
18y+y^2=360 \vee 18y+y^2=-360\\
y^2+18y+81=441 \vee y^2+18y+81=-279\\
(y+9)^2=441 \vee (y+9)^2=-279\\
y+9=\sqrt{441} \vee y+9=-\sqrt{441}\\
y=21-9 \vee y=-21-9\\
y=12 \vee y=-30\\\\
x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}$

4 0

2 years ago

Read 2 more answers

If x-9=2y and x+3=5y the what is the value of x

Slav-nsk [51]

For the first 1 X= 11 because all you need to do is add or subtract the numbers visible.
The second would be 2.

3 0

2 years ago

Read 2 more answers

Mean Value theorem help! BRAINLIEST if you can explain it clearly!!!

Korolek [52]

$\bf f(x)=ln(x-5)\qquad [6,8]\qquad \cfrac{df}{dx}=\cfrac{1}{x-5}\\\\
-----------------------------\\\\
\textit{mean value theorem}\qquad f'(c)=\cfrac{f(b)-f(a)}{b-a}\\\\
-----------------------------\\\\
f'(c)=\cfrac{1}{c-5}\qquad thus\quad \cfrac{1}{c-5}=\cfrac{f(8)-f(6)}{8-6}
\\\\\\
\cfrac{1}{c-5}=\cfrac{ln(3)-ln(1)}{2}\implies \cfrac{1}{c-5}=\cfrac{ln(3)-0}{2}
\\\\\\
\cfrac{2}{ln(3)}=c-5\implies \boxed{\cfrac{2}{ln(3)}+5=c}$

7 0

3 years ago

Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o

AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that $\mu = 490, \sigma = \sqrt{400} = 20$

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 490}{20}$

$Z = 0.5$

$Z = 0.5$ has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0

2 years ago

The diagram represents a 12cm by 4cm what is the area? ​

The diagram represents a 12cm by 4cm what is the area?