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Nastasia [14]
3 years ago
14

There are many three digit numbers that are each divisible by 7 and also 8 without a remainder.What is the largest of these thre

e digit numbers?
HELP PLEASE EXPLAIN!
Mathematics
1 answer:
Semenov [28]3 years ago
7 0
The largest number is 952. I'll tell you why...

7*8=56

------------

56*18=7*8*18=7*8*3*6=1008 (4 digits)

56*17=7*8*17=952 (3 digits)
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Answer:

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Step-by-step explanation:

Let's solve your equation step-by-step.

12−2(n−1)=−18

Step 1: Simplify both sides of the equation.

12−2(n−1)=−18

12+(−2)(n)+(−2)(−1)=−18(Distribute)

12+−2n+2=−18

(−2n)+(12+2)=−18(Combine Like Terms)

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Step 2: Subtract 14 from both sides.

−2n+14−14=−18−14

−2n=−32

Step 3: Divide both sides by -2.

−2n /−2  =  −32 /−2

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