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Lapatulllka [165]

3 years ago

5

A store pays $20 for a set of headphones. The store sells the set of headphones for $70. Your classmate says that the markup is

350% because$70/$20=3.5 Is your classmate correct?

2 answers:

-BARSIC- [3]3 years ago

6 0

Yes it is like if you got a 70/20 on a test. That would be a score of 350%

Natalija [7]3 years ago

4 0

Yes. your classmate is correct

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How many clubs have at least 30 members?

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Step-by-step explanation:

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2y^3-18y^2+9y-81<br> Factor the polynomial completely

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(y-9)(2y^2 +9)

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3 years ago

A cylindrical water bottle has a diameter of 5 in. and a height of 9 in. What is the capacity of the water bottle in cubic inche

VikaD [51]

The answer will be 388.6 because you will use the formula V=pi.r^2.h.
pi we know is 3.14 we also know that radius is half the diameter so half of 5 is 2.5 and the height is 9 so here is what we have so far. V=3.14x2.5^2x9.
2.5x2.5=13.75 13.75x3.14=43.175 43.175x9=388.575 and if we round that it will be 388.6 so your answer is 388.6

3 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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For the mean you add them all up and divide by the ammount of numbers you added. So it would be 118

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