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finlep [7]
3 years ago
14

Solve for y in simplest form: y^2+3y-4=0

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
y^2+3y-4=0 \\  \\ (y+4)(y-1)=0 \\  \\ y+4=0 \\ y=-4 \\  \\ y-1=0 \\ y=1 \\  \\ y=-4,1
Mashcka [7]3 years ago
5 0
Y^2+3y-4=o
y^2+4y-y-4=0
y(y+4)-1(y+4)=0
(y-1)(y+4)=o
y=1 or y=-4
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tiny-mole [99]

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3 years ago
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grandymaker [24]

Answer:

H) -6/13  

Step-by-step explanation:

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ehidna [41]

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Step-by-step explanation:

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3 years ago
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