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3 years ago

Solve for y in simplest form: y^2+3y-4=0

Mathematics

2 answers:

Effectus [21]3 years ago

8 0

$y^2+3y-4=0 \\ \\ (y+4)(y-1)=0 \\ \\ y+4=0 \\ y=-4 \\ \\ y-1=0 \\ y=1 \\ \\ y=-4,1$

Mashcka [7]3 years ago

5 0

Y^2+3y-4=o
y^2+4y-y-4=0
y(y+4)-1(y+4)=0
(y-1)(y+4)=o
y=1 or y=-4

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