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adell [148]
1 year ago
11

PLSS HELP ASAPPPPP!!!

Mathematics
2 answers:
goblinko [34]1 year ago
8 0

Answer:

Step-by-step explanation:

Answer:  Choice C

Equation is |x − 20| = 0.45

The min is x = 19.55

=====================================================

Explanation:

fl oz = fluid ounces

x = volume of the drink in fl oz

The expression |x-20| represents how far x is from the target of 20 fl oz. We use absolute value to ensure the result is never negative. It might help to draw out a number line.

Two examples:

If x = 22 then |x-20| = |22-20| = |2| = 2 which shows that 22 is 2 units away from 20 on the number line.

If x = 17 then |x-20| = |17-20| = |-3| = 3 which shows that 17 is 3 units away from 20 on the number line.

We want this difference to be within 0.45 fl oz, i.e. we want |x-20| to either equal 0.45 or be smaller than it.

If we only cared about the min and max, then we set |x-20| equal to 0.45 to generate the equation |x − 20| = 0.45

----------------

Solve this equation to find the min and max.

|x - 20| = 0.45

x-20 = 0.45 or x-20 = -0.45

x = 0.45+20 or x = -0.45+20

x = 20.45 or x = 19.55

The min is 19.55 fl oz and the max is 20.45 fl oz.

Phrased another way: the x values span from 19.55 to 20.45, inclusive of both endpoints. We could write  as a compact way to describe what values x could be.

ladessa [460]1 year ago
7 0
<h3>Answer:  Choice C</h3>

Equation is |x − 20| = 0.45

The min is x = 19.55

=====================================================

Explanation:

fl oz = fluid ounces

x = volume of the drink in fl oz

The expression |x-20| represents how far x is from the target of 20 fl oz. We use absolute value to ensure the result is never negative. It might help to draw out a number line.

Two examples:

  • If x = 22 then |x-20| = |22-20| = |2| = 2 which shows that 22 is 2 units away from 20 on the number line.
  • If x = 17 then |x-20| = |17-20| = |-3| = 3 which shows that 17 is 3 units away from 20 on the number line.

We want this difference to be within 0.45 fl oz, i.e. we want |x-20| to either equal 0.45 or be smaller than it.

If we only cared about the min and max, then we set |x-20| equal to 0.45 to generate the equation |x − 20| = 0.45

----------------

Solve this equation to find the min and max.

|x - 20| = 0.45

x-20 = 0.45 or x-20 = -0.45

x = 0.45+20 or x = -0.45+20

x = 20.45 or x = 19.55

The min is 19.55 fl oz and the max is 20.45 fl oz.

Phrased another way: the x values span from 19.55 to 20.45, inclusive of both endpoints. We could write 19.55 \le \text{x} \le 20.45 as a compact way to describe what values x could be.

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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

  • The interquartile range = <u>6075</u>

Learn more here:

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5 0
2 years ago
42 decreased by the product of 12 and a number is 6.
levacccp [35]
42 - 12x = 6
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4 0
3 years ago
Please I need help!!
Anastaziya [24]

Answer:

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Step-by-step explanation:

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2 years ago
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Vesnalui [34]

Hello! :)

The <u>answer</u> is x+15!

~Hope it helps!~ :)

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Ksju [112]
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