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adell [148]
1 year ago
11

PLSS HELP ASAPPPPP!!!

Mathematics
2 answers:
goblinko [34]1 year ago
8 0

Answer:

Step-by-step explanation:

Answer:  Choice C

Equation is |x − 20| = 0.45

The min is x = 19.55

=====================================================

Explanation:

fl oz = fluid ounces

x = volume of the drink in fl oz

The expression |x-20| represents how far x is from the target of 20 fl oz. We use absolute value to ensure the result is never negative. It might help to draw out a number line.

Two examples:

If x = 22 then |x-20| = |22-20| = |2| = 2 which shows that 22 is 2 units away from 20 on the number line.

If x = 17 then |x-20| = |17-20| = |-3| = 3 which shows that 17 is 3 units away from 20 on the number line.

We want this difference to be within 0.45 fl oz, i.e. we want |x-20| to either equal 0.45 or be smaller than it.

If we only cared about the min and max, then we set |x-20| equal to 0.45 to generate the equation |x − 20| = 0.45

----------------

Solve this equation to find the min and max.

|x - 20| = 0.45

x-20 = 0.45 or x-20 = -0.45

x = 0.45+20 or x = -0.45+20

x = 20.45 or x = 19.55

The min is 19.55 fl oz and the max is 20.45 fl oz.

Phrased another way: the x values span from 19.55 to 20.45, inclusive of both endpoints. We could write  as a compact way to describe what values x could be.

ladessa [460]1 year ago
7 0
<h3>Answer:  Choice C</h3>

Equation is |x − 20| = 0.45

The min is x = 19.55

=====================================================

Explanation:

fl oz = fluid ounces

x = volume of the drink in fl oz

The expression |x-20| represents how far x is from the target of 20 fl oz. We use absolute value to ensure the result is never negative. It might help to draw out a number line.

Two examples:

  • If x = 22 then |x-20| = |22-20| = |2| = 2 which shows that 22 is 2 units away from 20 on the number line.
  • If x = 17 then |x-20| = |17-20| = |-3| = 3 which shows that 17 is 3 units away from 20 on the number line.

We want this difference to be within 0.45 fl oz, i.e. we want |x-20| to either equal 0.45 or be smaller than it.

If we only cared about the min and max, then we set |x-20| equal to 0.45 to generate the equation |x − 20| = 0.45

----------------

Solve this equation to find the min and max.

|x - 20| = 0.45

x-20 = 0.45 or x-20 = -0.45

x = 0.45+20 or x = -0.45+20

x = 20.45 or x = 19.55

The min is 19.55 fl oz and the max is 20.45 fl oz.

Phrased another way: the x values span from 19.55 to 20.45, inclusive of both endpoints. We could write 19.55 \le \text{x} \le 20.45 as a compact way to describe what values x could be.

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Answer:

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Step-by-step explanation:

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3 years ago
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A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes
Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i

Which is not correct. The correct steps are shown below.

Using distributive property, we get

4(3-2i)+5i(3-2i)

4(3)+4(-2i)+5i(3)+5i(-2i)

12-8i+15i-10i^2

12+7i-10(-1)       [\because i^2=-1]

12+7i+10

22+7i

Therefore, the correct value of (4+5i)(3-2i) is 22+7i.

4 0
3 years ago
The mass of the Earth is 5.972x10^24 kg. the mass of the moon is 7.3 x 10^22kg. find the total mass, in kg, of the Earth and the
torisob [31]

Answer:

6045000000000000000000000 kg.

Step-by-step explanation:

We have been given that the mass of Earth is 5.972\times10^{24} kg. The mass of the Moon is 7.3\times10^{22} kg.

To find the total mass we will add mass of Earth and Moon.

First of all let us convert the given masses in standard form.

5.972\times10^{24}=5972000000000000000000000  

7.3\times10^{22}=73000000000000000000000

5.972\times10^{24}+7.3\times10^{22}  

5972000000000000000000000+73000000000000000000000

6045000000000000000000000

Therefore, the mass of Earth and Moon is 6045000000000000000000000 kg.

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