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kari74 [83]
3 years ago
12

What is Oxidation state of sulphur in Na2S4O6?Help me..​

Chemistry
1 answer:
quester [9]3 years ago
6 0

Answer:

oxidation state of sulphur=x

Explanation:

Na2S4O6=2[+1]+4x+6[-2]=0

                 +2+4x-12=0

                     4x-10=0

                           4x=10

                            x=10/4=2.5

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It is logical to conclude that water cannot dissolve vegetable oil because the oil is
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3 years ago
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How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26ÁC? Show all work used to solve this pr
klio [65]
The answer is 7.33 g.

<span>To calculate this, we will use the the ideal gas law:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.</span>

Since the amount of substance of gas (n) can be expressed as mass (m) divided by molar mass (M), then:

PV = RTm/M

It is given:

P = 0.98 atm

V = 10.2 l

T = 26°C = 299.15 K 

R = 0.082 l atm/Kmol (gas constant)

M (H2O) = 2Ar(H) + Ar(O) = 2*1 + 16 = 2 + 16 = 18g

m = ?

Since PV = RTm/M, then:

m = PVM/RT

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6 0
3 years ago
Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu
oksano4ka [1.4K]

Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, K=\frac{[B]}{[A]}>1

As, both 5000 and 8\times 10^{7} are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0
3 years ago
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