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Ray Of Light [21]
3 years ago
13

What are the coordinates of the midpoint of the segment whose endpoints are (-4,6) and (-8,-2)

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0
The formula to find the midpoint of a segment is ((x1 + x2)/2,),(y1 + y2)/2).

The x coordinate of the first point is -4, and the x coordinate of the second point is -8.  The y coordinate of the first point is 6, and the y coordinate of the second point is -2.  Now, we can plug these into our formula.

((-4 + (-8))/2), (6 + (-2))/2)) = (-12/2), (4/2) = (-6, 2)

So, (-6, 2) is the midpoint of the segment.
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What is the standard form of the equation of a circle whose diameter is 20 units and whose center is (−1,7)?
VARVARA [1.3K]

Answer:

(x + 1)^2 + (y - 7)^2 = 100

Step-by-sep explanation:

Given:

Diameter of circle = 20 units

Center of circle = (-1, 7)

Standard form of the equation of a circle is expressed in the center-radius form as:

(x - h)^2 + (y - k)^2 = r^2,

Where,

h = -1

k = 7

r = ½ of diameter = ½(20) = 10 units

Plug in the values into the equation

(x - h)^2 + (y - k)^2 = r^2

(x - (-1))^2 + (y - 7)^2 = 10^2

(x + 1)^2 + (y - 7)^2 = 100

4 0
3 years ago
Which is the equation of the linear model?
Zielflug [23.3K]
The answer is B. y =  0.75 + 2.25. because i've done this assement.

3 0
3 years ago
It would be great if someone could help me with this problem
GaryK [48]
Y-intercept (0, 1)
Equation of asymptote y=0

Equation of asymptote can also be called horizontal asymptote.
It means the place where the line almost meets but actually not touching the place. The line almost touches y=0 but it actually does not touch it.

7 0
3 years ago
Calculate the surface area and volume of the shape below.
pav-90 [236]

Surface area

Let's calculate the surface area of the rectangular block. It has length, width and height of L = 15, W = 5, H = 8. The surface area is going to be

SA = 2*(LW+WH+LH)

SA = 2*(15*5+5*8+15*8)

SA = 470

This is without the cylinder attached to the top surface. If we account for that, then we'll have to subtract off the area of the circle covered up which is

pi*r^2 = pi*3^2 = 9pi = 28.27433 approximately

So 470-28.27433 = 441.72567 is the approximate surface area of the rectangular block after we subtract off the circular portion covered up by the cylinder.

----------

The lateral surface area of the cylinder is approximately

2*pi*r*h = 2*pi*3*4 = 24pi = 75.39822

Which adds onto the top circular area of 28.27433 to get 28.27433+75.39822 = 103.67255

Meaning that 103.67255 is the surface area for the cylinder portion. Again we don't worry about the bottom portion as it's not part of the outer surface.

---------

Overall, the total surface area of this compound 3D figure is

(surface area for rectangular portion) + (surface area cylinder portion) = 441.72567+103.67255 = 545.39822

When rounding to the nearest whole number, the total surface area is about 545 square cm

<h3>Answer: 545 square cm</h3>

============================================================

Volume

The rectangular block has volume L*W*H = 15*5*8 = 600 cubic cm

The cylinder has volume pi*r^2*h = pi*3^2*4 = 113.0973355 approximately

Add the two volumes to get 600+113.0973355 = 713.0973355 and this rounds to 713. We don't have to do any subtraction in this section.

<h3>Answer: 713 cubic cm</h3>
4 0
3 years ago
Please help
Tamiku [17]
Add 6 7 and two you get 15 xy subtract -11 and -4 you get  positive 7xy add 15 and 7 and you get 22xy
8 0
3 years ago
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