Consider the quadratic equation ax2 + bx +5 = 0, where a,b, and c are rational numbers and the quadratic has two disticnt zeros.

Mathematics

1 answer:

Afina-wow [57]2 years ago

4 0

Step-by-step explanation:

x2 + bx +5 = 0,

where a,b and c are rational numbers.

Also it is given that the quadratic has 2 distinct zeros and one of it's zero is irrational.

We know that if it has a one irrational zero, the conjugated couple of the one zero is also a null with the same polynomial balance for a polynomial equation with rational coefficients." Therefore, in this case it is a quadratic equation, one is null and irrational; thus, the other zero is irrational.

You might be interested in

What value of X makes the equation true?<br><br> 12x-15=16-3x

gogolik [260]

X= 2 1/15 or 31/15.

4 0

3 years ago

What is the location of the point (5, 0) translates 4 units to the down and reflected across the y-axis?

CaHeK987 [17]

STEP-BY-STEP EXPLANATION:

Given information

The given ordered point = (5, 0)

Step 1: We need to translate the point 4 units down

To translate down means we will be subtracting a value from the y--axis

Hence, we have

$\begin{gathered} (x,\text{ y) }\rightarrow\text{ (x, y-b)} \\ \text{where b = 4} \\ (5,\text{ 0) }\rightarrow\text{ (5, 0 - 4)} \\ (5,\text{ 0) }\rightarrow\text{ (5, -4)} \end{gathered}$

When translated 4 units down, we got (5, -4)

Step 2: Reflect over the y-axis

The general rule for reflecting over the y-axis is (-x, y)

This means the value of x will be negated and the value of y will remain the same