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2 years ago

15

Consider the quadratic equation ax2 + bx +5 = 0, where a,b, and c are rational numbers and the quadratic has two disticnt zeros.

1 answer:

Afina-wow [57]2 years ago

4 0

Step-by-step explanation:

x2 + bx +5 = 0,

where a,b and c are rational numbers.

Also it is given that the quadratic has 2 distinct zeros and one of it's zero is irrational.

We know that if it has a one irrational zero, the conjugated couple of the one zero is also a null with the same polynomial balance for a polynomial equation with rational coefficients." Therefore, in this case it is a quadratic equation, one is null and irrational; thus, the other zero is irrational.

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3 years ago

Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T

myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

$\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375$

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

$\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375$

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

$\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

$\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

$\text{P(at least one head)} = \dfrac{7}{8} = 0.875$

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

$\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

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3 years ago

What is the value of the expression 2^2+6^2÷2^2

Studentka2010 [4]

Answer:

13

Step-by-step explanation:

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0r

4 + (6/2)^2 = 4+ 3^2 = 4+9 = 13

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2 years ago