Answer:
0.004462m²
612000m²
0.0482m²
Step-by-step explanation:
Using the conversion
1mm² = 10^-6m²
4462mm² = x
Cross multiply
1 * x = 4462 * 10^-6
x = 4462 * 10^-6
x = 4.462 * 10^3 * 10^-6
x = 4.462*10^{3-6}
x = 4.462*10^-3
x = 0.004462m²
Hence 4462 mm² in m² is 0.004462m²
0.612 km² in m²
1km² = 10^6m²
0.612km² = y
Cross multiply
1 * y = 0.612 * 10^6
y = 0.612*1,000,000
y = 612000m²
Hence 0.612 km² in m² is 612000m²
482 cm² in m²
1cm² = 0.0001m²
482 cm² = z
z = 482 * 0.0001
z = 0.0482m²
Hence 482 cm² in m² is 0.0482m²
First you would simplify the equation <span>(7x²+2x+5)+(3x²-8x-10) lets start with the first part
</span><span>(7x²+2x+5)
</span>7x² + 2x which = 49x + 2x which also = 51x Then you add the last part (+5)
51x + 5
Now you simplify the last part.
<span>(3x²-8x-10)
</span>3x²-8x which=9x - 8x which also = 1x or simply x Then add the last part (-10) Which you'll get x-10
51x + 5) + (x - 10) = 52x -5
so your answer is 52x - 5
Answer:
625 ft^2
Step-by-step explanation:
Given
--- perimeter
Required
The largest area
The perimeter is calculated as:

So, we have:

Divide both sides by 2

Make L the subject

The area is calculated as:

Substitute 

Open bracket

Differentiate with respect to W

Set to 0; to get the maximum value of W

Collect like terms

Divide by -2

So, the maximum area is:




(B) - Yes, because the amount owed changes by 2.25 every time the miles change by 1.
Starting at 1 mile the price is 2.5 dollars.
Mile 2 is 4.75 dollars. What is the difference between 4.75 and 2.5? 2.25
Mile 3 is 7 dollars. What is the difference between 7 and 4.75? 2.25
Mile 4 is 9.25 dollars. What is the difference between 9.25 and 7? 2.25
Mule 5 is 11.5 dollars. What is the difference between 11.5 and 9.25? 2.25
The change is always 2.25 dollars.
The change is 2.25 dollars per mile.
One way to solve for this is (11.5 - 2.5)/(5-1)=2.25
This is (y2-y1)/(x2-x1). By picking 2 points, (x1,y1) and (x2,y2) you can solve for the slope (rate of change) between them.
A^2 = 4.0^2 + 3.7^3 - 2*4*3.7 cos 334
= 4.865
a = 2.2 to nearest tenth.