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3 years ago

Please help me with this one

Mathematics

1 answer:

skad [1K]3 years ago

5 0

Answer:

71.51

Step-by-step explanation:

A=ah+bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=3·3+7·3+7·3+1

2·﹣34+2·(3·7)2+2·(3·7)2﹣74+2·(7·7)2﹣74=71.51219

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Which of the following would be a possible solution to the system of inequalities given below?

Nataly [62]

Answer:

(0,5)

Step-by-step explanation:

we have

$2x+3y > 12$ ----> inequality A

$x-y\leq 1$ ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities of the system (makes true both inequalities)

Verify each ordered pair

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B and then compare the results

case 1) (0,5)

For x=0,y=5

Inequality A

$2(0)+3(5) > 12$

$15 > 12$ ----> is true

The ordered pair satisfy inequality A

Inequality B

$0-5\leq 1$

$-5\leq 1$ ---> is true

The ordered pair satisfy inequality B

therefore

The ordered pair would be a solution of the system

case 2) (5,2)

For x=5,y=2

Inequality A

$2(5)+3(2) > 12$

$16 > 12$ ----> is true

The ordered pair satisfy inequality A

Inequality B

$5-2\leq 1$

$3\leq 1$ ---> is not true

The ordered pair not satisfy inequality B

therefore

The ordered pair is not a solution of the system

case 3) (0,4)

For x=0,y=4

Inequality A

$2(0)+3(4) > 12$

$12 > 12$ ----> is not true

The ordered pair not satisfy inequality A

therefore

The ordered pair is not a solution of the system

case 4) (6,0)

For x=6,y=0

Inequality A

$2(6)+3(0) > 12$

$12 > 12$ ----> is not true

The ordered pair not satisfy inequality A

therefore

The ordered pair is not a solution of the system

5 0

4 years ago

Please help me (: <img src="https://tex.z-dn.net/?f=help" id="TexFormula1" title="help" alt="help" align="absmiddle" class="l

Dima020 [189]

Answer:

C) y=-4x-3 making pancakes

5 0

3 years ago

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Alvin throws the football to a receiver who jumps up to catch the ball. The height of the ball over time can be represented by t

Mandarinka [93]

Answer:

The standard form of the equation is 49t² - 75t + 3 = 0

The solution of the equations are 1.49 and 0.041

Step-by-step explanation:

* Lets explain how to solve the problem

- The standard form of the quadratic equation is ax² + bx + c = 0,

where a , b , c are constant and a can not be 0

∵ The quadratic equation is -4.9t² + 7.5t + 1.8 = 2.1

- Lets make the left hand side equal to 0

∵ -4.9t² + 7.5t + 1.8 = 2.1 ⇒ subtract 2.1 from both sides

∴ -4.9t² + 7.5t - 0.3 = 0 ⇒ multiply each term by -10

∴ 49t² - 75t + 3 = 0

* The standard form of the equation is 49t² - 75t + 3 = 0

∵ ax² + bx + c = 0

∴ a = 49 , b = -75 , c = 3

- Lets use the formula $x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$ to solve

the equation

∴ $x=\frac{-(-75)+\sqrt{(-75)^{2}-4(49)(3)}}{2(49)}=1.49$

∴ $x=\frac{-(-75)-\sqrt{(-75)^{2}-4(49)(3)}}{2(49)}=0.041$

* The solution of the equations are 1.49 and 0.041

6 0

3 years ago

Convert 15 km per hour to meters per second

ipn [44]

1km = 1000m
1hr = 3600sec

Do proportions:
1km / 1000m = 15km / x
15000m = x

1hr = 3600sec

15000/3600 = 4.2m per second
Choice 4

6 0

3 years ago

What is the reciprocal of 5/6

mestny [16]

Answer:

-6/5

Hope this helps!

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3 years ago

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