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Trava [24]
2 years ago
11

Please help me with this one

Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

71.51

Step-by-step explanation:

A=ah+bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=3·3+7·3+7·3+1

2·﹣34+2·(3·7)2+2·(3·7)2﹣74+2·(7·7)2﹣74=71.51219

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What is 9x + 18 = 6y - 3x for y ​
Nana76 [90]

Answer: 2x+3

Step-by-step explanation:

9x+18=6y-3x Our goal is to isolate y.

Let's add 3x to both sides of the equation to cancel out that -3x on the right side.

12x+18=6y Because all of these integers are divisible by the gcf of 6, we can divide both sides of the equation by 6.

2x+3=y

4 0
3 years ago
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diamong [38]

Answer:

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2 years ago
Help pls I dont know​
liubo4ka [24]
14 and -18 would be less than or equal too when the -y makes them -14 and 18 it is still less than 19
5 0
2 years ago
Read 2 more answers
Factor completely 3a4y3 − 12a3y2 + 6a2y.
Firlakuza [10]

Step-by-step explanation:

3a^4y^3-12a^3y^2+6a^2y=(3a^2y)(a^2y^2)-(3a^2y)(4ay)+(3a^2y)(2)\\\\=(3a^2y)(a^2y^2-4ay+2)

5 0
2 years ago
Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx
yawa3891 [41]

\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}

Expand the numerator as

x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2

Then in the limit,

\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}

3 0
2 years ago
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