Question

{[20/(8+2)]^6+6}/(4^2/2)

Answer 1

{[20 ÷ (8 + 2)]⁶ + 6} ÷ (4² ÷ 2)
{[20 ÷ 10]⁶ + 6} ÷ (16 ÷ 2)
{[2]⁶ + 6} ÷ 8
{64 + 6} ÷ 8
70 ÷ 8
8.75

Answer 2

So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)