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Illusion [34]
3 years ago
7

A store display rotates 40 times every half hour. How many times will the display rotate in 4 hours?

Mathematics
1 answer:
Ket [755]3 years ago
5 0
<span>A store display rotates 40 times every half hour i.e 30 minutes
Thus, by simple calcultion, we say,
Therefore, the store display rotates 80 times in 1 hour i.e. 60 minutes
Now, 
Thus, the strore display will rotate 80*4 = 320 times in 4 hours

therefore, the answer is 320 times in 4 hours</span>
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Plzzz help<br> What is the distance between P(-3, -2) and Q(5, -2)?
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Question 6 of 6
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\huge \boxed { \sf \: Answer}

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2 years ago
Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)
timama [110]
<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\

Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

6 0
2 years ago
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