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2 years ago

What is the product?

Mathematics

2 answers:

RSB [31]2 years ago

4 0

Answer:

15a^5b^15

Step-by-step explanation:

you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.

sukhopar [10]2 years ago

4 0

Answer:

15 a^5 b^15

Step-by-step explanation:

3 a^2 b^7 * 5a^3 b^8

We know x^y * x^z = x^(y+z)

3*5 a^(2 +3) b^(7+8)

15 a^5 b^15

You might be interested in

The combined area of a square and a rectangle is 225 square yards. the length of the rectangle is 8 times the width of the recta

snow_lady [41]

Answer:

The rectangle: L = 40 yards. W = 5 yards

The square: The length and width are both 5 yards.

Step-by-step explanation:

Let L and W be the length and width of the rectangle.

Let l and w be the length and width of the square.

Area for each is:

Rectangle: L*W

Square: l*w

We are told that L*W + l*w = 225 yards^2

We are also told that

L = 8W

and that

l = W

Since the sides of a square are all equal, w is also W: w=W

Summarizing and substituting:

L*W + l*w = 225 yards^2

(8W)*W + W*W = 225 yards^2

8W^2 + W^2 = 225 yards^2

9W^2 = 225 yards^2

W^2 = 25

W = 5 feet

---------------------

Therefore, since L = 8W , L = 40 yards. W = 5 yards for the rectangle.

The square: l=W, so l = 5 yards, and thus w=5 yards

--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

5 0

1 year ago

Nine times a number decreased by 4 yields four times the number increased by 16

Eva8 [605]

The answer would be the following:
9 x - 4 = 4x + 16

8 0

2 years ago

Consider the initial value function y given by

Nuetrik [128]

Answer:

y(s) = $\frac{5s-53}{s^{2} - 10s + 26}$

we will compare the denominator to the form $(s-a)^{2} +\beta ^{2}$

$s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$

comparing coefficients of terms in s

$s^{2} :$ 1

s: -2a = -10

a = -2/-10

a = 1/5

constant: $a^{2}+\beta ^{2} = 26$

$(\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09$

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = $A(s-a)+B((s-a)^{2} +\beta ^{2} )$

we insert the values of a and β

$\\5s-53$ = $A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )$

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

the constants are

a = 0.2

β = 5.09

A = 5.4

B = -2

Step-by-step explanation:

since the denominator has a complex root we compare with the standard form $s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$
Expand and compare coefficients to obtain the values of a and β as shown above
substitute the values gotten into the function
Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0

2 years ago

20 equals 5 times negative 3 plus x

kotykmax [81]

Answer:

20=5*-3+x or 20=-15+x or 35=x

8 0

3 years ago

Which option summarizes what gave Chandra Gupta I power

mars1129 [50]

Answer:

Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.

Step-by-step explanation:

6 0

3 years ago