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3 years ago

Mrs. Baker found 25 shells on the beach. She brought 2/5 of the shells to her

Mathematics

2 answers:

Basile [38]3 years ago

8 0

Answer:

A. 10 B. 15

Step-by-step explanation:

A. 25/1 * 2/5= 50/5

reduced it is 10

B. 25-10=15

nikklg [1K]3 years ago

3 0

Answer:

she brought 10 shells to her classroom and 15 shells to her house. Hope that helps!

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The area of a rectangle is 36 square centimeters and its length is 9 centimeters

Andrei [34K]

A) 4 cm
B) 9 cm x 12 cm
C) 108 cm

8 0

3 years ago

Need help due tomorrow plz help!!

Sonbull [250]

1.) B

because it says the person buys a ski for 350. He puts down $110 which means to subtract. Now he got a discount which also means to subtract. Then it told that he gave 1/2 them money to his mother. So that too means to subtract.

2.) 2+5n

because it says 2 plus 5 times a number. So 2+5×n

6 0

3 years ago

The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the

12345 [234]

Answer:

$4x^2-21x-2$

Step-by-step explanation:

Given that:

Difference of two trinomials is $x^2 - 10x + 2$

One of the two trinomials is $3x^2 - 11x - 4$

To find:

The other trinomial = ?

Four options are:

$2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2$

Solution:

Let the two trinomials be A and B.

Given A - B = $x^2 - 10x + 2$

B = $3x^2 - 11x - 4$

We have to find the other trinomial A.

A - B = $x^2 - 10x + 2$

A - ( $3x^2 - 11x - 4$ ) = $x^2 - 10x + 2$

$\Rightarrow$ A = $x^2 - 10x + 2$ + ( $3x^2 - 11x - 4$ )

$\Rightarrow$ A = $4x^2-21x-2$

So, the correct answer is $4x^2-21x-2$ .

3 0

3 years ago

What could be the next statement that Ivan makes his proof?

natali 33 [55]

Answer: Choice A) Triangle ABC is similar to triangle ACD by AA

AA stands for Angle Angle. Specifically it means we need 2 pairs of congruent angles between the two triangles in order to prove the triangles similar. Your book might write "AA similarity" instead of simply "AA".

For triangles ABC and ACD, we have the first pair of angles being A = A (angle A shows up twice each in the first slot). The second pair of congruent angles would be the right angles for triangle ABC and ACD, which are angles C and D respectively.

We can't use AAS because we don't know any information about the sides of the triangle.

7 0

3 years ago

Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:

professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is $\{1,2,3,4\}$ .

a) We need to find a relation R reflexive and transitive that contain the relation $R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}$

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

1R4 and 4R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
4R1 and 1R2, then 4 must be related with 2.

Therefore $\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\}$ is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

since 1R2, then 2 must be related with 1.
since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

1R2 and 2R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
2R1 and 1R4, then 2 must be related with 4.
4R1 and 1R2, then 4 must be related with 2.
2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

1 must be related with 1,

2 must be related with 2,

3 must be related with 3,

4 must be related with 4

For be symmetric

since 1R2, 2 must be related with 1,
since 1R4, 4 must be related with 1.

For be transitive

Since 4R1 and 1R2, 4 must be related with 2,
since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

5 0

3 years ago