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sergiy2304 [10]

3 years ago

8

|(3a+2)-4(a-2)|=7 what is one possible value for a A) -13 B)-3 C)1 D)17

1 answer:

oee [108]3 years ago

4 0

The answer to the question is b

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Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,

$\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}$

a) Thus, the equation is

$\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n$

b) 1960 is n=0; thus,

$f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots$

The answer to part b) is $1.113043... per hour

c)1996 is n=36

$\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}$

The model prediction is above $5.15 by $0.55 approximately. The answer is 'below'

4 0

1 year ago

Rahm used a payment plan to purchase wood for a home project. The wood he bought cost $500. The clerk at the store offered him t

faust18 [17]

Answer: 210

Step-by-step explanation:

55×12=660-500=160+50(down payment)=210

5 0

4 years ago

PLS HELP I'LL MARK BRAINLIEST

Elis [28]

Answer:

Domain: (-∞, -5) ∪ (-1, ∞)

Step-by-step explanation:

Note:

For f(x) > 0: See the points of x for which the graph of f(x) lies above the x-axis.

For f(x) < 0: See the points of x for which the graph of f(x) lies below the x-axis.

We need to find the domain of f(x) for which f(x) < 0

From the graph, we can tell:

f(x) < 0 on (-∞, -5) ∪ (-1, ∞)

Therefore: The domain on which the given graph f(x) is negative, is (-∞, -5) ∪ (-1, ∞)

6 0

2 years ago

The local library has a children’s section with picture books and chapter books. The ratio is 2:3. If there are a total of 500 b

PolarNik [594]

Answer:

300, I think.

8 0

4 years ago

Read 2 more answers

How to solve (p^2)^5

Damm [24]

Explanation: The power rule tells us that when we have a power taken to another power, we keep the base the same and we multiply the exponents.

So we have p¹⁰ which is our final answer.

4 0

4 years ago