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3 years ago

1. -12(x+4)=602. 9(x-4)=81solve for x

Mathematics

1 answer:

Oduvanchick [21]3 years ago

3 0

Answer:

1. x=-9

2.x=13

Step-by-step explanation:

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4 years ago

Lucas esta buscando piso. ¿que oferta tiene el mejor precio por m cuadrado? VILLASUR ENSANCHE: superficie: 0,75 dam cuadrados su

Jet001 [13]

Answer:

Area 1 is the best option

Step-by-step explanation:

Given Data:

Area 1 = 0.75 dam square

Price = €11,620

Area 2 = 0.009 ha

at €193,500

Area 3 = 0.84a

at €68,900

Where ha ( hectare )

a ( area )

Solution

First we convert all areas to square meter ( m² )

Area 1 = 100 * 0.75 dam square

= 75m²

Cost of area 1/ square meter

= €11,620 / 75m²

= €154.93 / square meter

Area 2 = 0.009 ha * 10,000

= 90m²

Cost of area 2 / square meter

= €193,500 / 90m²

= €2,150 / square meter

Area 3 = 0.84a * 100

= 84m²

= Cost of area 3 / square meter

= €68,900 / 84m²

= €820.23 / square meter

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4 years ago

Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

The question is incomplete:

The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31.

The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15.

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

4 years ago

The sales tax T on an article is equal to the tax rate R times the selling price P of the article

disa [49]

I can't provide the answer. But...I can provide examples.

Hope these help!

https://www.mathstips.com/sales-tax-trade-tax/

5 0

3 years ago

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1. -12(x+4)=602. 9(x-4)=81solve for x​

1. -12(x+4)=602. 9(x-4)=81solve for x