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2 years ago

If 9/10 of cats prefer felix food of the total 500 surveyed,how many do NOT prefer felix

Mathematics

1 answer:

gregori [183]2 years ago

6 0

Answer:

450 cats do NOT prefer felix

Step-by-step explanation:

9/10= x/500

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Match the rates with their equivalent unit rates. Match the rates with their equivalent unit rates. arrowRight arrowRight arrowR

anyanavicka [17]

Answer:

$\frac{47}{2} \to 6$

$\frac{60}{12} \to 5$

$\frac{40}{10} \to 4$

$\frac{56}{8} \to 7$

$\frac{64}{8} \to 8$

Step-by-step explanation:

Given

See attachment

Required

Complete the blanks

To do this, we simply carry out the division operation.

So, we have:

$\frac{47}{2} \to 6$

$\frac{60}{12} \to 5$

$\frac{40}{10} \to 4$

$\frac{56}{8} \to 7$

$\frac{64}{8} \to 8$

6 0

2 years ago

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How to solve this problem

mylen [45]

I think. 2 over 3a3 + 3a2 - 3

5 0

2 years ago

A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te

garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

A one tailed test is a test that have hypothesis of the form

$H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu$

A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
Rejection region is the area for which the null hypothesis is rejected.
If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.

If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0

2 years ago

HELP ME!!!

AVprozaik [17]

Answer:

Hi.. Your answer is last...

6x/8=3

3 0

2 years ago

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Solve 3m+7/2=−2m+5/2 what is m

GenaCL600 [577]

Solve for m:3 m + 7/2 = 5/2 - 2 m
Put each term in 3 m + 7/2 over the common denominator 2: 3 m + 7/2 = (6 m)/2 + 7/2:(6 m)/2 + 7/2 = 5/2 - 2 m
(6 m)/2 + 7/2 = (6 m + 7)/2:(6 m + 7)/2 = 5/2 - 2 m
Put each term in 5/2 - 2 m over the common denominator 2: 5/2 - 2 m = 5/2 - (4 m)/2:(6 m + 7)/2 = 5/2 - (4 m)/2
5/2 - (4 m)/2 = (5 - 4 m)/2:(6 m + 7)/2 = (5 - 4 m)/2
Multiply both sides by 2:6 m + 7 = 5 - 4 m
Add 4 m to both sides:6 m + 4 m + 7 = (4 m - 4 m) + 5
4 m - 4 m = 0:6 m + 4 m + 7 = 5
6 m + 4 m = 10 m:10 m + 7 = 5
Subtract 7 from both sides:10 m + (7 - 7) = 5 - 7
7 - 7 = 0:10 m = 5 - 7
5 - 7 = -2:10 m = -2
Divide both sides of 10 m = -2 by 10:(10 m)/10 = (-2)/10
10/10 = 1:m = (-2)/10
The gcd of -2 and 10 is 2, so (-2)/10 = (2 (-1))/(2×5) = 2/2×(-1)/5 = (-1)/5:Answer: m = (-1)/5

5 0

3 years ago

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