Note the general equation of a circle is x^2 + y^2 = r^2, with centre (0, 0) and radius: r.
So, our equation of a circle is (x + 3)^2 + (y - 1)^2 = 100
Subtract 100 from both sides and plug in the points. If it equals to 0, then the points satisfy the equation of the circle (ie lies on the circle)
2/3 + 5/6
= 4/6 + 5/6
= 9/6
= 3/2
A. 3/2
Answer:
Volume of pyramid = 317 units³
Step-by-step explanation:
Volume do triangular pyramid = ⅓ × Base Area × height of pyramid
Base area = ½*bh = ½*8*14 = 56 units²
Height of pyramid = 17
Volume of pyramid = ⅓ × 56 × 17
Volume of pyramid = 317 units³ (to nearest whole number)
Answer:

Step-by-step explanation:
<u>Angles in a Circle</u>
An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.
Segments AE and DE are secants of the given circle. They form an exterior angle called AED.
The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.
Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:


