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densk [106]
3 years ago
15

What output is produced by the following code? Integer first = new Integer(7); Integer second = first; if (first == second) Syst

em.out.println("Sneezy"); else System.out.println("Grumpy"); if (first.equals(second)) System.out.println("Sleepy"); else System.out.println("Doc"); Sneezy Sleepy Sneezy Doc Grumpy Sleepy Grumpy Doc
Computers and Technology
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

The correct output of this question is  "Sneezy Sleepy".

Explanation:

In the given code firstly we create the object of the integer class that is first in this we pass the integer value that is 7. Then we declare another second integer variable is this variable we pass object as a reference. Then we use the two conditional statements. In the first, if block we check that the object of the class is equal to the reference variable. If it is true it prints Sneezy. otherwise, it will print Grumpy. In second if block we check that the object of the class is equal to the reference variable. but in this time we the equals() function it is the same as(==). If the condition is true it prints Sleepy. otherwise, it will print Doc. So the output of the code is Sneezy Sleepy.

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There are different methods of writing programs such as python and others. However, in this case, it is pertinent to know that this compiler that will return true if the lower four bits of x are the same as the lower four bits of y doesn't accept binary constants and as such we will use hexidecimal instead. For example; for 0b00111111, we will use 0x3F.]

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