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BigorU [14]
3 years ago
7

Implement a function called merge that does the following in C#:

Computers and Technology
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Check the explanation

Explanation:

using System;

using System.Collections.Generic;

using System.Linq;

public class Problem2

{

public static IEnumerable<int> merge (IEnumerable<int> input1, IEnumerable<int> input2, IEnumerable<int> input3)

{

IList<int> list = new List<int>();

foreach (int i in input1)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

foreach (int i in input2)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

foreach (int i in input3)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

return list;

}

}

public class Problem2Demo{

static void Main (string[] args)

{

Random rnd = new Random ();

var list1 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var list2 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var list3 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var answer = Problem2.merge (list1, list2, list3);

foreach (int i in answer)

{

Console.WriteLine (i);

}

}

Kindly check the attached output image below.

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We will use linear interpolation in a C program to estimate the population of NJ between the years of the census, which takes pl
nikklg [1K]

Answer:

See explaination for program code

Explanation:

program code below:

#include<stdio.h>

int main()

{

//file pointer to read from the file

FILE *fptr;

//array to store the years

int years[50];

//array to store the population

float population[50];

int n = 0, j;

//variables for the linear interpolation formula

float x0,y0,x1,y1,xp,yp;

//opening the file

fptr = fopen("njpopulation.dat", "r");

if (fptr != NULL)

{

//reading data for the file

while(fscanf(fptr, "%d %f", &years[n], &population[n]) == 2)

n++;

//prompting the user

int year = -1;

printf("Enter the years for which the population is to be estimated. Enter 0 to stop.\n\n");

while(year != 0)

{

printf("Enter the year (1790 - 2010) : ");

scanf("%d", &year);

if (year >= 1790 && year <= 2010)

{

//calculating the estimation

xp = year;

for (j = 0; j < n; j++)

{

if (year == years[j])

{

//if the year is already in the table no nedd for calculation

yp = population[j];

}

else if (j != n - 1)

{

//finding the surrounding census years

if (year > years[j] && year < years[j + 1])

{

//point one

x0 = years[j];

y0 = population[j];

//point two

x1 = years[j + 1];

y1 = population[j + 1];

//interpolation formula

yp = y0 + ((y1-y0)/(x1-x0)) * (xp - x0);

}

}

}

printf("\nEstimated population for year %d : %.2f\n\n", year, yp);

}

else if (year != 0)

{

printf("\nInvalid chioce!!\n\n");

}

}

printf("\nAborting!!");

}

else

{

printf("File cannot be opened!!");

}

close(fptr);

return 0;

}

OUTPUT :

Enter the years for which the population is to be estimated. Enter 0 to stop.

Enter the year (1790 - 2010) : 1790

Estimated population for year 1790 : 184139.00

Enter the year (1790 - 2010) : 1855

Estimated population for year 1855 : 580795.00

Enter the year (1790 - 2010) : 2010

Estimated population for year 2010 : 8791894.00

Enter the year (1790 - 2010) : 4545

Invalid chioce!!

Enter the year (1790 - 2010) : 1992

Estimated population for year 1992 : 7867020.50

Enter the year (1790 - 2010) : 0

Aborting!!

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