Your answer would be C. Internet since we all use the internet everyday to communicate through all over the world. We can currently communicate to the other side of the world with little to no effort now, almost 10 years ago it would of been very difficult.
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
Answer:
long power(int i)
{
return pow(2,i);
}
Explanation:
The above written function is in C++.It does not uses loop.It's return type is long.It uses the function pow that is present in the math library of the c++.It takes two arguments return the result as first argument raised to the power of second.
for ex:-
pow(3,2);
It means 3^2 and it will return 9.
