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Marrrta [24]
3 years ago
15

The negative sign can be read as "the opposite of." true or false

Mathematics
2 answers:
Svetach [21]3 years ago
8 0

Answer:

true

Step-by-step explanation:

Alex777 [14]3 years ago
5 0
True if you’re solving for a solution but if it’s the solution has a negative since it can’t be read as positive
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URGENT!
Tamiku [17]
Slope=y2-y1/x2-x1
Slope=1.2-0/2-0
Slope= 0.6
3 0
3 years ago
Read 2 more answers
Evaluate f(x) = 5x2 - 4x - 9 for f(-2)
Svetllana [295]

Answer:

99

Step-by-step explanation:

5x^2 -4x -9

5(-2)^2 -4(-2) -9

-10^2 +8 -9

100-1

99

8 0
4 years ago
AXYZ has vertices X(-4,2), Y(4.2), and Z(0, - 1). Is AXYZ scalene, isosceles, or equilateral?
ivolga24 [154]

Answer:

Isosceles triangle.

Step-by-step explanation:

In order to determine the nature of the triangle, we will need to get the sides XY, XZ and YZ using the distance formula;

For XY;

X(-4,2), Y(4.2)

XY = √(2-2)²(4-(-4)²)

XY = √(4+4)²

XY = √8²

XY = 8

For XZ;

X(-4,2), Z(0, - 1)

XZ = √(-1-2)²(0-(-4))²

XZ = √(-3)²+4²

XZ = √9+16

XZ = √25

XZ = 5

For XZ;

Y(4.2), Z(0, - 1)

YZ = √(-1-2)²(0-(4))²

YZ = √(-3)²+(-4)²

YZ = √9+16

YZ = √25

YZ = 5

Since XZ = YZ = 5, this shows that two sides are equal. Hence the triangle is an isosceles triangle.

NB: Isosceles triangle only have two of its sides and angles equal

5 0
3 years ago
Guys plzz help <br> I will give points plzzz​
ludmilkaskok [199]

Answer:

Pizza

Step-by-step explanation:

It’s yummy

4 0
3 years ago
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
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