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3 years ago

39/28 express as a mixed number

Mathematics

1 answer:

xeze [42]3 years ago

5 0

We can do this easily. Since we know that the numerator is more than the denominator, we need to know by how much.

39-28=11; It's only 11 more, which means 11/28 would be the fraction and the whole number is 1.

39/28= 1 11/28

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I’m pretty sure that it is the 3 or C option.

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3 years ago

Choose the algebraic description that maps the image ΔABC onto ΔA′B′C′.

murzikaleks [220]

The algebraic description that maps the image ΔABC onto ΔA′B′C′ is (x, y) ⇒ (x + 7, y - 4)

<h3>What is transformation?</h3>

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2 years ago

How many different license plates are possible if a license plate consists of 2 capital letters followed by 5 digits?

Alina [70]

The first letter can be any one of 26 letters. For each one . . .
The second letter can be any one of 26 letters. For each one . . .

The first digit can be any one of 10 digits. For each one . . .
The second digit can be any one of 10 digits. For each one . . .
The third digit can be any one of 10 digits. For each one . . .
The fourth digit can be any one of 10 digits. For each one . . .
The fifth digit can be any one of 10 digits.

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6 0

3 years ago

Read 2 more answers

A rock is dropped from the top of a 2000-foot building. After 1 second, the rock is traveling 32 feet per second. After 2 second

alexandr402 [8]

Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.

To find the rate of decent you would multiply the rate by time:

The equation is y = 32x

B. Replace x with 15 and solve for y:

Y = 32(15)

Y = 480

The rate of speed is 480 feet per second.

8 0

2 years ago

for the given license plate configuration, determine how many different plates are possinle if letters and digits (a) can ba rep

Inessa05 [86]

Answer:

a) 1,757,600 different plates possible.

b) 1,404,000 different plates possible.

Step-by-step explanation:

The permutations formula is important to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

(a) can be repeated:

There are 3 letters, each one with 26 possible outcomes.

2 digits, each with 10 possible outcomes

T = 26*26*26*10*10 = 1757600

1,757,600 different plates possible.

(b) cannot be repeated:

Here the permutations formula is used.

Three letters, from a set of 26.

Two digits, from a set of 10. So

$T = P_{(26,3)}*P_{(10,2)} = \frac{26!}{(26-3)!}*\frac{10!}{(10-2)!} = 1404000$

1,404,000 different plates possible.

4 0

3 years ago