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EastWind [94]
3 years ago
11

A regression analysis between sales (y in $1000) and advertising (x in dollars) resulted in the following equation y = 50,000 +

6x.
The above equation implies that an:

A. increase of $6 in advertising is associated with an increase of $6,000 in sales.
B. increase of $1 in advertising is associated with an increase of $6 in sales.
C. increase of $1 in advertising is associated with an increase of $56,000 in sales.
D. increase of $1 in advertising is associated with an increase of $6,000 in sales.
Mathematics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

D. increase of $1 in advertising is associated with an increase of $6,000 in sales.

Step-by-step explanation:

Every dollar in advertisting is multiply by 6 in the equation, but every unit in y represent $1000. That means that $1 1n advertisting is multiply by 6 and then by $1000, that is $1 in advertisting = $6000 in sales.

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What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2?
Slav-nsk [51]

Hello from MrBillDoesMath!

Answer:

1/ 91.4

Discussion:

Evaluate  1/ ( 3x^3 + 5.2y)   when x = 3, y = 2.

1/ (3 (3)^3 + 5.2(2))  =

1/ ( 3 * 27 + 10.4) =

1/ ( 81 + 10.4) =

1/ (91.4) =

.0109 (approx)

Thank you,

MrB

6 0
3 years ago
Find unit rate $112.00 in 5 hours = per hour​
Sedbober [7]

Answer:

22.4

Step-by-step explanation:

112 ÷ 5 is 22.4.

7 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=K" id="TexFormula1" title="K" alt="K" align="absmiddle" class="latex-formula"> be a circle
yan [13]

The bisector of angle APQ passes through O and this is illustrated below.

<h3>How to illustrate the information?</h3>

From the information given, the center is O. and the circle passes through O and cuts at K.

In this case, it should be noted that the circles are equal according to the SAS test.

Here, AOB + APQ = 180° (Linear pair)

2AOB = 180

AOB = 90.

Therefore, the bisector of angle APQ passes through O.

Learn more about bisector on:

brainly.com/question/11006922

#SPJ1

8 0
2 years ago
Given the data, as shown in the image below, determine if the distribution is uniformly distributed, symmetrically distributed,
Sedbober [7]

Answer:

The distribution is symmetric.

Step-by-step explanation:

<em>The distribution will be skew left, if the data is more distributed on left side of graph.</em>

<em>The distribution will be right left, if the data is more distributed on right side of graph.</em>

<em>The distribution is symmetric if from the center, the data is distributed symmetrically, equal increase or decrease on either side.</em>

<em>The distribution is uniform if the value of data remains constant throughout the graph.</em>

Above here, the from the center, the data decreases symmetrically on both the sides, same values of data for Cat-Rabbit pair and Dog-Mice pair.

Thus, distribution is symmetric.

8 0
2 years ago
6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0
2 years ago
Read 2 more answers
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