Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
It would be a special purposes map :)
Answer:
P(Spinner lands on purple section) = 0.6 = 60%
Step-by-step explanation:
We are given the following in the question:
Number of sections = 10
Number of purple sections = 6
a) probability that the spinner will land on purple purple
P(purple) =

0.6 is the probability that the spinner will land on purple purple.
b) Interpretation of probability

There is a 60% chance that the spinner will land on purple color.
Answer:
x ≈ 9.6
Step-by-step explanation:
Δ ABC is right with ∠ C = 90° ( angle between tangent and radius )
Using Pythagoras' identity in the right triangle
x² + 14² = 17²
x² + 196 = 289 ( subtract 196 from both sides )
x² = 93 ( take the square root of both sides )
x =
≈ 9.6 ( to the nearest tenth )
Answer: Your answer is 48%
Step-by-step explanation: