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Marrrta [24]
3 years ago
12

3) 14, 9, 20, 5, 17, 13 mean: median: mode: range:​

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

mean: 13

range: 15

there is no mode

median: 13.5

Step-by-step explanation:

mean= 14+9+20+5+17+13 = 78

78÷6= 13

range = highest number minus the smallest number

20-5 = 15

the mode is the number that occurs the most

median= 13+14= 27

27÷2 = 13.5

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To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of
tia_tia [17]

Answer:

2.89, rounded to the nearest hundredth

Step-by-step explanation:

Given that GPA is weighted by credits, we must first multiply each grade by its credit amount and sum those up to weigh the credits. Then, we divide by the total amount of credits to get the GPA per credit.

So, we start with math,

3.7 *5 + 1.8 *3 + 2.8 * 5 + 2.8 * 4 = 49.1 as the total GPA weighted per credit.

Then, to find the average per credit, we divide by the total amount of credits, which is 5 + 3 + 5 + 4 = 17.

Our answer is 49.1/17 = 2.89, rounded to the nearest hundredth

4 0
3 years ago
The height of a falling object is given by h(t) = 400 − 39t − 157e−t/4 with h in meters and t in seconds. Assuming that the grou
Vlad1618 [11]
This is the concept of algebra; given that the height of the house at time t is given by:
h(t)=<span> 400 − 39t − 157e−t/4
the velocity of the house is given by:
dh/dt
velocity of our object is:
dh/dt=-39+1/4*157e^-(t/4)
=-39+157/4 e^(-t/4)
thus the velocity at h=0 will be as follows:
at h=0, the value of t will be:
0=400-39t-157e^(-t/4)
solving for t we get:
t=-5.4 or t=10.1
since we don't have negative time, t=10.1
thus the velocity at this point will be:
dh/dt=-38+1/4*157e^(-10.1/4)
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this means that the object dropped by a velocity of 38.86 sec</span>
5 0
3 years ago
What is 216847.314 rounded by the nearest liter
erica [24]
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3 0
3 years ago
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tangare [24]

13-4x = 13 -4(-8) = 13 +32 = 45

7 0
2 years ago
Read 2 more answers
A local radio station had a contest to see who could guess closest to the actual number of jellybeans that filled a small car. t
Allushta [10]
Given:
Number of jelly beens in the car: 785,000
Number of jelly beans in a bag: 800

Number of bags needed to fill the car?

785,000 / 800 = 981.25

Randall claimed = more than 981 bags
Susie claimed = exactly 981 bags.

Randall is correct. More than 981 bags.

981 x 800 = 784,800  

There is a missing 200 jelly beans if exactly 981 bags were used. Thus, a quarter of the 982nd bag is used to complete the 785,000 jelly beans. 
4 0
3 years ago
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