Kino said that if play practice does not start on time, the director “will be mad”.
The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively
<h3>The value of P(A)</h3>
The event A is given as:
A : Sum greater than 6
In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes
This means that:
P(A) = 21/36
Simplify
P(A) = 7/12
<h3>The value of P(B)</h3>
The event B is given as:
B : Sum is divisible by 2
In the sample space of a roll of two dice, there are 18 outcomes that are divisible by 2, out of a total of 36 outcomes
This means that:
P(B) = 18/36
Simplify
P(B) = 1/2
Hence, the probability values of P(A) and P(B) are 7/12 and 1/2, respectively
Read more about probability at:
brainly.com/question/251701
#SPJ1
Hjgsjgsjgek zhfsurznf. Bsyeruqkhckh sjgwkgeidkgegkw jaws
Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
First one A and D
Second A and C
Third A and D
Fourth 20 / 4 = X
X = 5
Step-by-step explanation:
