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solniwko [45]
4 years ago
9

The questions are on the pictures ( I’m sorry there are so much pictures I couldn’t make the page smaller) :(

Mathematics
2 answers:
77julia77 [94]4 years ago
3 0

Answer: A

Step-by-step explanation:

sdas [7]4 years ago
3 0

Answer:

3rd one is false

2nd one is D

1st one is A

Step-by-step explanation:

I think the 2nd and 1st one is right im not positive but i tried

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Natali5045456 [20]
500 / 100 = 5          5 x 15 = 75        75 x 4 = 300     300 + 500 = 800
After the loan, you will pay $800. Hope this helps :)
4 0
3 years ago
Looking for someone who can take a look at this question for me:
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There are
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8 red balls
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4 0
3 years ago
Please answer the question
soldi70 [24.7K]
The formula is side squared+(2)(side)(height)=answer
So 10x10=100,
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The answer is 260.
4 0
4 years ago
Read 2 more answers
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
Y= 3x-1<br> 2x+6=y substitution method
vfiekz [6]

Answer: (7, 20)

Concept:

There are three general ways to solve systems of equations:

  1. Elimination
  2. Substitution
  3. Graphing

Since the question has specific requirements, we are going to use <u>substitution </u>to solve the equations.

Solve:

<u>Given equations</u>

y = 3x - 1

2x + 6 = y

<u>Substitute the y value since both equations has isolated [y]</u>

2x + 6 = 3x - 1

<u>Add 1 on both sides</u>

2x + 6 + 1 = 3x - 1 + 1

2x + 7 = 3x

<u>Subtract 2x on both sides</u>

2x + 7 - 2x = 3x - 2x

\boxed{x=7}

<u>Find the value of y</u>

y = 3x - 1

y = 3(7) - 1

y = 21 - 1

\boxed{y=20}

Hope this helps!! :)

Please let me know if you have any questions

3 0
3 years ago
Read 2 more answers
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