Answer:
e
Step-by-step explanation:
of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.
Lets count...
3a...thats 1 term
3ab...thats 2
7b....thats 3
-2c....movin on up to 4
-4d....and we end at 5
so this expression has 5 terms since none of the terms can be combined :)