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Phoenix [80]
3 years ago
9

What us the approximate length of the diameter,d?

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r = radius\\[-0.5em] \hrulefill\\ C=44 \end{cases}\implies 44=2\pi r\implies \cfrac{44}{2\pi }=r\implies \cfrac{22}{\pi }=r \\\\\\ \stackrel{\textit{diameter is 2r}}{2\cdot \cfrac{22}{\pi }}\implies \cfrac{44}{\pi }\qquad \approx \qquad 14.00563499208679

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Hello :
x =(1/4)y²
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3 years ago
Given the parent functions f(x) = 3x 2 and g(x) = 5x − 10, what is g(x) − f(x)? (2 points)
Assoli18 [71]
$\begin{align} g(x)-f(x)&=(5x-10)-(3x+2)\\&=(5x-3x)+(-10-2)\\&=\boxed{2x-12} \end
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3 years ago
A diamond can be classified as either gem-quality or industrial-grade. 80% of diamonds are classified as industrial-grade.
mote1985 [20]

Answer:

a) 0.64

b) 0.21

c) 0.79

Step-by-step explanation:

Percentage of industrial-grade diamonds = 80%

This means, if one diamond is chosen at random, there is 80% chance that it will be of industrial-grade. So,

P(Industrial grade) = 80% = 0.80

Part a)

Probability that 1st diamond is industrial-grade = 0.80

Since, selection of diamonds in independent, the probability that 2nd diamond is also industrial grade = 0.80

The overall probability of both diamonds being industrial-grade will be the product of their individual probabilities, according to the fundamental rule of counting.

So, if two diamonds are chosen at random, the probability that both are industrial grade = 0.80 x 0.80 = (0.80)² = 0.64

Part b)

Following the same logic as we followed in the previous part.

The probability of each of the 7 diamonds being industrial-grade is 0.80, so the probability that all 7 are industrial grade will be:

Probability = 0.80 x 0.80 x 0.80 x 0.80 x 0.80 x 0.80 x 0.80 = (0.80)^{7} = 0.21

So, if 7 diamonds are chosen at random, the probability that all 7 are industrial grade is 0.21.

Part c)

The event "at least one" is complement of event "none". So, the event "at least one of 7" will be complement of "none of the 7"

If none of the selected diamonds is gem quality, this means all 7 of the diamonds are industrial-grade. So,

The probability that none of the diamonds is gem-quality = The probability that all 7 are industrial-grade = 0.21

So,

The probability that at least one of the 7 selected diamonds is gem-quality = 1 - Probability that none is gem-quality

= 1 - 0.21

= 0.79

Since the probability that atleast one of the 7 randomly selected diamonds is gem-quality is greater than 0.05, it won't be unusual event.

3 0
3 years ago
What is 829×2929-(920)×0​
musickatia [10]

Answer:

0

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Internet Pricing An Internet Service Provider (ISP) offers its customers three options:
Mama L [17]

Answer:

(b)$29.62

(c)$5.73

Step-by-step explanation:

Basic: Standard internet for everyday needs, at $24.95 per month.

Premium: Fast internet speeds for streaming video and downloading music, at $30.95 per month.

Ultra: Super-fast internet speeds for online gaming at $40.95 per month.

Let the number of customers on Ultra=x; therefore:

Number of Premium customers =2x

Number of Basic customers =3x

Total=x+2x+3x=6x

P(Ultra)=\dfrac{x}{6x}=\dfrac{1}{6}  \\P(Premium)=\dfrac{2x}{6x}=\dfrac{1}{3}\\P(Basic)=\dfrac{3x}{6x}=\dfrac{1}{2}

(a)X=Monthly fee paid by a randomly selected customer.

Therefore, the probability distribution of X is given as:

\left|\begin{array}{c|c}X&P(X)\\---&---\\\$24.95&3/6\\\$30.95&2/6\\\$40.95&1/6\end{array}\right|

(b)Average Monthly Revenue per customer

Mean,

\mu=(\$24.95 \times 3/6)+(\$30.95 \times 2/6)+(\$40.95 \times 1/6)\\=\$29.62

(c)Standard Deviation

\left|\begin{array}{c|c|c|c|c}x&P(x)&x-\mu &(x-\mu)^2&(x-\mu)^2P(x)\\-----&-----&----&----&-----\\\$24.95&3/6&-4.67&21.8089&10.9045\\\$30.95&2/6&1.33&1.7689&0.5896\\\$40.95&1/6&11.33&128.3689&21.3948\\-----&-----&----&----&-----\\&&&&32.8889\end{array}\right|

\text{Standard Deviation}=\sqrt{(x-\mu)^2P(x)}\\=\sqrt{32.8889} \\ \sigma=\$5.73

4 0
3 years ago
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