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3 years ago

9

What us the approximate length of the diameter,d?

1 answer:

zhenek [66]3 years ago

3 0

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r = radius\\[-0.5em] \hrulefill\\ C=44 \end{cases}\implies 44=2\pi r\implies \cfrac{44}{2\pi }=r\implies \cfrac{22}{\pi }=r \\\\\\ \stackrel{\textit{diameter is 2r}}{2\cdot \cfrac{22}{\pi }}\implies \cfrac{44}{\pi }\qquad \approx \qquad 14.00563499208679$

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Mathematicians, please check my work

kodGreya [7K]

The answer that you said is right. I totally agree with you.

3 0

3 years ago

Is (-3,2)(−3,2)left parenthesis, minus, 3, comma, 2, right parenthesis a solution of -4x -10y < -9−4x−10y<−9minus, 4, x, m

r-ruslan [8.4K]

Answer:

The answer to your question is The point (-3, 2) is not a solution

Step-by-step explanation:

Inequality

- 4x - 10y < - 9

-point (-3, 2)

Process

1.- To solve this problem, just substitute the point in the inequality and simplify

a) Substitution

-4(-3) - 10(2) < - 9

b) Simplification

12 - 20 < - 9

c) Result

- 8 < - 9

This is false, -8 > -9

7 0

2 years ago

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = $(x+4)$ days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

I will give brainliest Select the expression equivalent to

Neko [114]

It’ll be the first one

6 0

2 years ago

Two angels of a triangle measure 65 and 75. Which is not the measure of an exterior angle of the triangle

Andre45 [30]

An exterior angle is the sum of the two other interior angles

<span>the three interior angles are 55 and 65 and 180-(55+65)=60 </span>

<span>so 60 + 55 = 115 </span>
<span>60 + 65 = 125 </span>
<span>65 + 55 = 120
</span>
brainlest answer.

3 0

3 years ago