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4 years ago

What us the approximate length of the diameter,d?

Mathematics

1 answer:

zhenek [66]4 years ago

3 0

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r = radius\\[-0.5em] \hrulefill\\ C=44 \end{cases}\implies 44=2\pi r\implies \cfrac{44}{2\pi }=r\implies \cfrac{22}{\pi }=r \\\\\\ \stackrel{\textit{diameter is 2r}}{2\cdot \cfrac{22}{\pi }}\implies \cfrac{44}{\pi }\qquad \approx \qquad 14.00563499208679$

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Help with this algebra problem? 12y+6=6y+12?

Anika [276]

First, combine like terms.
12y+6=6y+12 turns into
12y-6y=12-6, which is
6y=6. Now divide both sides by 6.
y=1

now do a quick check (cause that's always a good idea).
12(1)+6=6(1)+12
12+6=6+12
18=18 ; )

7 0

3 years ago

What equation could be used to find the value of x? (ANSWER QUICK)

kykrilka [37]

Answer:

2(5.5x -1.5) + 2(6x +2.5) = 94 (You may want to simplify!)

Step-by-step explanation:

add up to perimeter which = 94

5 0

2 years ago

How does adding the log together automatically mean that it is a factorial?

andreyandreev [35.5K]

Answer: The answer is given below.

Step-by-step explanation: We are given an equality involving logarithm and we are to show the implication of L.H.S. to R.H.S.

We will be using the following two properties of logarithm:

$(i)~\log_ba=\dfrac{1}{\log_ab},\\\\\\(ii)~log_ab+\log_ac=\log_a(bc).$

The proof is as follows:

$L.H.S.\\\\\\=\dfrac{1}{\log_2N}+\dfrac{1}{\log_3N}+\dfrac{1}{\log_4N}+\cdots+\dfrac{1}{\log_{100}N}\\\\\\=\log_N2+\logN3+\log_N4+\cdots+\log_N100\\\\=\log_N\{2.3.4...100\}\\\\=\log_N\{1.2.3.4...100\}\\\\=\log_N{100!}\\\\=\dfrac{1}{\log_{100!}N}\\\\=R.H.S.$

Hence proved.

6 0

3 years ago

570 mL = ____ oz show step by step

Rzqust [24]

Solutions

570 ml to oz is: <span>19.27399 Ounces
</span>
= 19.27

3 0

4 years ago

Read 2 more answers

Write the sum of the numbers as the product of their GCF and another sum. Show your work. Can you guys help me please and explai

Gre4nikov [31]

The distributive property: a(b + c) = ab + ac

-------------------------------------------------------------------

Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56

Factors of 64: 1, 2, 4, 8, 16, 32, 64

GCF(56, 64) = 8

56 = 8 · 7

64 = 8 · 8

56 + 64 = 8 · 7 + 8 · 8 = = 8(7 + 8)

--------------------------------------------------------------------

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54

GCF(30, 54) = 6

30 = 6 · 5

54 = 6 · 9

30 + 54 = 6 · 5 + 6 · 9 = 6(5 + 9)

5 0

3 years ago