Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

92% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Answer:
no clue bro sorry
Step-by-step explanation:
most likely d
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
Amount invested = $396
Interest rate = 13% per year
Time = 3 years
We will use the "Exponential growth formula" i.e.

Here,
P denotes Principle amount
r denoted rate of growth
t denotes number of years,
So, it becomes

Hence, First option is correct.