a test is worth 80 points multiple choice questions are worth 2 points and short answer questions are worth 4 points if the test
2 answers:
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Answer:
His annual payment rate required to pay off the loan in 7 years is a year.
He has to pay $11026.85 in interest
Step-by-step explanation:
The first step to solve this problem is find how much the student will have to pay for the car. So, we have to find how much the present value of the car(in $) will be worth in 7 years. This is a compound interest problem:
The compound interest formula is given by:
Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.
In this exercise, we have:
A = The value we want to find
P = The initial value = 5510
r = 0.17
n = 1
t = 7
So
In a seven year period, he has to pay $16536.85. Per year, he has to pay a rate k of:
His annual payment rate required to pay off the loan in 7 years is
How much does he pay in interest?
His loan is $5510 and he has to pay $16536.85. So, in interest, he has to pay
<span><u><em>The correct answer is:</em></u>
16%.
<u><em>Explanation</em></u><span><u><em>: </em></u>
We use a z-score to answer this question.
<u>The formula for a z-score is:</u>
z=</span></span>
<span><span>,
where mue is the mean and sigma is the standard deviation.
<u>Using our information, we have:</u>
z=</span></span>
<span><span>.
Using a z-table, we see that the area to the left of, or less than, this score is 0.8413. We want to know how many students scored more than this, so we subtract from 1:
1-0.8413=0.1587, which rounds to 16%.</span></span>
16%.
<u><em>Explanation</em></u><span><u><em>: </em></u>
We use a z-score to answer this question.
<u>The formula for a z-score is:</u>
z=</span></span>
where mue is the mean and sigma is the standard deviation.
<u>Using our information, we have:</u>
z=</span></span>
Using a z-table, we see that the area to the left of, or less than, this score is 0.8413. We want to know how many students scored more than this, so we subtract from 1:
1-0.8413=0.1587, which rounds to 16%.</span></span>