Answer:
The area of triangle is 
Step-by-step explanation:
we know that
The area of a triangle is equal to
A=(1/2)bh
we have
b=8 1/3 m
convert to an improper fraction
8 1/3 m=(8*3+1)/3=25/3 m
The fourth root of 16 is equal to 2
![\sqrt[4]{16}=(2^{4})^{1/4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%282%5E%7B4%7D%29%5E%7B1%2F4%7D%3D2)
so
h=2 m
substitute

convert to mixed number

Answer:

Step-by-step explanation:
To solve this, we are using the average rate of change formula:

where
is the average rate of change
is the first point
is the second point
is the function evaluated at the first point
is the function evaluated at the second point
We want to know the average rate of change of the function
form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words,
and
.
Replacing values







We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is 
NOTES:
- squared (²) means multiply that number by itself 2 times
- cubed (³) means multiply that number by itself 3 times
- square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
- cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
Answer: (C) 41
<u>Step-by-step explanation:</u>
![\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41](https://tex.z-dn.net/?f=%5Cquad%206%5E2%2B%5Csqrt%5B3%5D%7B125%7D%20%5C%5C%3D%206%20%5Ccdot%206%2B%5Csqrt%5B3%5D%7B5%5Ccdot%205%20%5Ccdot%205%7D%5C%5C%3D%2036%20%2B%205%5C%5C%3D%2041)
***************************************************************************************
Answer: (C) 10
<u>Step-by-step explanation:</u>
![\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B27%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B81%7D)
![=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}](https://tex.z-dn.net/?f=%3D%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B3%5Ccdot%203%20%5Ccdot%203%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B9%5Ccdot%209%7D)





***************************************************************************************
8² = 8 · 8 = 64 11² = 11 · 11 = 121
5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27
![\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%7D%3D4)
![\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8000%7D%3D%5Csqrt%5B3%5D%7B20%5Ccdot%2020%5Ccdot%2020%7D%3D20)