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nirvana33 [79]
3 years ago
6

What is the domain and range of this

Mathematics
1 answer:
Bond [772]3 years ago
6 0
Domain: What are all the possible x values?
[-6, 0) U (0,2)

[ ] Closed brackets means including a number
( ) Open brackets means not including that number

Range: All possible y values
(1, 6]
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Read 2 more answers
The boy wants to build rectangular beetle cages to study beetle behavior. He wants all the sides on the base of his cages to be
kap26 [50]

Answer:

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

Step-by-step explanation:

<u><em>The complete question is</em></u>

A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?

we know that

The number 576 decompose in prime factors is the same that write

576=(2^6)(3^2)

To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)

3x3=9cm                  2x2x2x2x2x2= 64cm  ----> is not a combination (one side is not greater than 10)

3x3x2= 18cm            2x2x2x2x2= 32cm

3x3x2x2= 36cm        2x2x2x2= 16cm

3x2x2= 12cm             3x2x2x2x2= 48cm

3x2x2x2= 24cm         3x2x2x2= 24cm

therefore

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

3 0
3 years ago
Find the area to the right of the z-score 1.39 and to the left of the z-score 1.53 under the standard normal curve.1.2 1.3 1.4 0
svetoff [14.1K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is  P( 1.39 <  z <  1.53 ) = 0.0193

Step-by-step explanation:

From the question we are told to obtain the area to the of the z-score 1.39 and to the left of the z-score 1.53, this is mathematically represented as

        P( 1.39 <  z <  1.53 ) =  P( z <  1.53 ) - P( z <  1.39 )

From the z table on the question the area under the normal curve to the left corresponding to 1.53 and  1.39  is

       P( z <  1.53 )  = 0.9370

and

      P( z <  1.39 )  = 0.9177

So

     P( 1.39 <  z <  1.53 ) = 0.9370 - 0.9177

=>  P( 1.39 <  z <  1.53 ) = 0.0193

6 0
3 years ago
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