Answer: 14 cakes
Step-by-step explanation:
We have the following data:
Number of gallons the baker has: ![4 gallons \frac{16 cups}{1 gallon}=64 cups](https://tex.z-dn.net/?f=4%20gallons%20%5Cfrac%7B16%20cups%7D%7B1%20gallon%7D%3D64%20cups)
Number of cups the baker used for one cake: ![4,5 cups](https://tex.z-dn.net/?f=4%2C5%20cups)
Now, we can use the Rule of three to find the maximum number of cakes the baker can completely decorate:
-----![1 cake](https://tex.z-dn.net/?f=1%20cake)
-----![?](https://tex.z-dn.net/?f=%3F)
Then:
![?=\frac{(64 cups)(1 cake)}{4.5 cups}](https://tex.z-dn.net/?f=%3F%3D%5Cfrac%7B%2864%20cups%29%281%20cake%29%7D%7B4.5%20cups%7D)
![?=14,2 cakes \approx 14 cakes](https://tex.z-dn.net/?f=%3F%3D14%2C2%20cakes%20%5Capprox%2014%20cakes)
After you combine like terms you will get 5p - 9m.
-3p + 8p is the same thing as 8p - 3, so you get 5p.
-2m + (-7m) is -9m
-3p and 8p are like terms.
-2m and -7m are also like terms.
Answer:
you switch 8x and 4y by subtracting 8x to 4y + 16 and substracting 4y to 8x.
This gives you the equation -4y = -8x+16
Then you divide each side by -4
To give you your slope-intercept form which is y = 2x-4.
The surface area<span> of a right </span>prism<span> can be calculated using the following formula: SA 5 2B 1 hP, where B is the </span>area<span> of the base, h is the height of the </span>prism<span>, and P is the perimeter of the base. The </span>lateral area<span> of a figure is the </span>area<span> of the non-base faces only.</span>
I believe the answer would be B, good luck