Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
Yes it is indeed nothing else can be done to this problem
First, we can simplify it down.
x = (-x + 6)^2
Then, you should have x - (
- 12x + 36).
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.
Answer:
x =0
Step-by-step explanation:
4+5e^x+2 =11
Combine like terms
6 + 5e^x =11
Subtract 6 from each side
6-6 + 5e^x =11-6
5 e^x = 5
Divide by 5 on each side
5 e^x /5 = 5/5
e^x = 1
Take the natural log on each side
ln (e^x) = ln(1)
x = ln(1)
x =0
